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What are the factors that influence the speed of the direct-current shunt motor with increasing load?
.The magnitude of the voltage and current of both the armature and shunt field coil. To decrease the speed when the load is increasing then increase the shunt field current while decreasing the armature voltage or current. To increase the speed while the load is increasing then increase the armature current while decreasing the shunt field current. The decreasing and increasing of these currents and voltages can be done by connecting a variable resistor in series or parallel with each of the armature and/or shunt field coil.
What effects causes the difference in terminal voltage between the increasing and decreasing field excitation current?
sdrg
What is the formula for armature resistance of shunt excited DC generator?
The armature resistance of a shunt excited DC generator is calculated using the formula ( R_a = \frac{V - E}{I_a} ), where ( R_a ) is the armature resistance, ( V ) is the terminal voltage, ( E ) is the generated EMF (electromotive force), and ( I_a ) is the armature current. The difference between the terminal voltage and the generated EMF accounts for the voltage drop across the armature resistance due to the current flowing through it.
How do you calculate armature current in a shunt generator?
To calculate the armature current in a shunt generator, you first need to determine the load current (I_load) and the shunt field current (I_shunt). The armature current (I_a) can then be calculated using the formula: ( I_a = I_{load} + I_{shunt} ). The shunt field current can be found using the field resistance and the terminal voltage. Once you have both currents, simply add them to find the total armature current.
What kind of current flows in the armature conductor of a dc generator?
pogi current flow in the armature conductor
What are the factors that influence the speed of the direct-current shunt motor with increasing load?
.The magnitude of the voltage and current of both the armature and shunt field coil. To decrease the speed when the load is increasing then increase the shunt field current while decreasing the armature voltage or current. To increase the speed while the load is increasing then increase the armature current while decreasing the shunt field current. The decreasing and increasing of these currents and voltages can be done by connecting a variable resistor in series or parallel with each of the armature and/or shunt field coil.
What effects causes the difference in terminal voltage between the increasing and decreasing field excitation current?
sdrg
How will the armature current and the output power of a dc shunt motors change with increasing load?
With increasing torque load the armature tends to slow down; the motor draws more current to compensate, and if there is armature resistance the back emf generated by the armature falls to allow the increased current to flow, which causes the motor to settle at a lower speed. The mechanical output power is the speed times the torque, and increasing the torque increases the power output provided the speed does not drop much.
What is the formula for armature resistance of shunt excited DC generator?
The armature resistance of a shunt excited DC generator is calculated using the formula ( R_a = \frac{V - E}{I_a} ), where ( R_a ) is the armature resistance, ( V ) is the terminal voltage, ( E ) is the generated EMF (electromotive force), and ( I_a ) is the armature current. The difference between the terminal voltage and the generated EMF accounts for the voltage drop across the armature resistance due to the current flowing through it.
How do you calculate armature current in a shunt generator?
To calculate the armature current in a shunt generator, you first need to determine the load current (I_load) and the shunt field current (I_shunt). The armature current (I_a) can then be calculated using the formula: ( I_a = I_{load} + I_{shunt} ). The shunt field current can be found using the field resistance and the terminal voltage. Once you have both currents, simply add them to find the total armature current.
What is the excitation system in a generator used for?
The excitation system is used to control the excitation of the rotating field in the armature. By increasing the armature current, it in turn increases the magnetic flux in the armature coil. This has the effect of increasing the voltage output of the generator. By lowering the armature current this in turn lowers the generator output voltage. The generator's voltage regulator automatically adjusts the output voltage continuously as the applied load on the generator changes.
How can you increase a current in a wire?
Ohm's law. Current is directly proportional to the applied emf and inversely proportional to the resistance in the circuit.
How can the current in a conductor be increased?
The current in a conductor can be increased by either increasing the voltage applied across the conductor or decreasing the resistance of the conductor.
What kind of current flows in the armature conductor of a dc generator?
pogi current flow in the armature conductor
What is armature current?
Armature current is the current flowing in a motor's armature. The "armature" is another name for the coil (or coils) of wire which are on the motor's "rotor", which is the part that rotates inside its stator. (The "stator" is the fixed, non-rotating part of the motor.)
Why does external voltage U decrease more with shunt than with separate excitation?
In shunt excitation, the field winding is connected in parallel with the armature, which means that the field current is influenced by the armature current. As load increases, the armature current rises, leading to a higher voltage drop across the armature resistance, which reduces the terminal voltage more significantly than in separate excitation. In separate excitation, the field winding has a constant supply independent of the armature current, maintaining a more stable voltage output under varying loads. Therefore, shunt excitation results in a greater decrease in external voltage due to the combined effects of increased armature current and associated voltage drop.
If A generator has an armature resistance of 0.6 ohms and when connected to a load of 40.9 ohms passes a current of 3.5 A what is the terminal voltage and generated EMF?
145.25 v
