include <iostream>
using namespace std;
int main() {
int n; // number to convert to binary
while (cin >> n) {
if (n > 0) {
cout << n << " (decimal) = ";
while (n > 0) {
cout << n%2;
n = n/2;
}
cout << " (binary) in reverse order" << endl;
} else {
cout << "Please enter a number greater than zero." << endl;
}
}
return 0;
}//end main
Assuming the number is represented by a decimal integer, initialise a counter to zero, then repeatedly divide the number by 10 and until the number is zero. After each division, examine the remainder. Each time the remainder is zero, increment the counter. If the number is represented by a decimal float, repeatedly multiply by 10 until the value is an integer, then perform the previous algorithm.
write a c++ program to convert binary number to decimal number by using while statement
public class Dataconversion { public static void main(String[] args) { System.out.println("Data types conversion example!"); int in = 44; System.out.println("Integer: " + in); //integer to binary String by = Integer.toBinaryString(in); System.out.println("Byte: " + by); //integer to hexadecimal String hex = Integer.toHexString(in); System.out.println("Hexa decimal: " + hex); //integer to octal String oct = Integer.toOctalString(in); System.out.println("Octal: " + oct); } }
x -=y;
This is not a question.
prompt x floor(x + .5) -> x disp x
5 is an integer; it is a whole number without a decimal or fraction.
Assuming the number is represented by a decimal integer, initialise a counter to zero, then repeatedly divide the number by 10 and until the number is zero. After each division, examine the remainder. Each time the remainder is zero, increment the counter. If the number is represented by a decimal float, repeatedly multiply by 10 until the value is an integer, then perform the previous algorithm.
write a c++ program to convert binary number to decimal number by using while statement
public class Dataconversion { public static void main(String[] args) { System.out.println("Data types conversion example!"); int in = 44; System.out.println("Integer: " + in); //integer to binary String by = Integer.toBinaryString(in); System.out.println("Byte: " + by); //integer to hexadecimal String hex = Integer.toHexString(in); System.out.println("Hexa decimal: " + hex); //integer to octal String oct = Integer.toOctalString(in); System.out.println("Octal: " + oct); } }
You first write the integer part, then write the decimal point and then the fractional part in decimal form.
Reference:cprogramming-bd.com/c_page2.aspx# reverse number
To write -45 as a decimal, you simply write "-45.0" or "-45.00" to indicate the number includes a whole number and decimal point. The decimal form of -45 represents the same value as the integer -45, but with a decimal point to show its position on the number line. The negative sign indicates that the number is less than zero.
To write 50,000 as an integer, you simply write the number without any decimal or fractional parts. In this case, 50,000 is already an integer because it is a whole number with no decimal or fractional component. Therefore, you can express 50,000 as an integer by writing it as "50,000."
pongada punda vayanungala ..................
The reason you're having so much difficulty writing it is that there's no such thing as an "interger". An "integer" is a whole number. Any time you write a number that doesn't have any fraction or decimal in it, you have written an integer.
x -=y;