#include<stdio.h>
main()
{
int a,b;
printf("enter the value for a and b\n");
scanf("%d %d",&a,&b);
display(a,b);
}
display(int x,int y)
{
int temp;
temp=x;
x=y;
y=temp;
printf("%d %d",x,y);
}
To write a C++ program to display the student details using class and array of object.
12
Yes, when you write a program that stores a value in a variable, you are utilizing storage to hold that value in memory. The variable acts as a named reference to the data, allowing the program to access and manipulate it as needed. This storage can be temporary (like in RAM) during program execution, or it can be persistent if saved to a more permanent medium, such as a file or database. Overall, managing storage is essential for effective data handling in programming.
The required c program is given below /*Swapping(interchange) the two entered numbers*/ #include<stdio.h> main() { /*Without using third variable*/ int a,b,t; printf("Enter a:"); scanf("%d",&a); printf("Enter b:"); scanf("%d",&b); a=a+b; b=a-b; a=a-b; printf("\n After swapping without using third variable"); printf("\na=%d\nb=%d",a,b); }
If you had an array int numbers[10]; you would do it like this: CODE: int lowestnumber = numbers[0]; for(int i = 0; i < 10; i++){ if(numbers[i] < lowestnumber) lowestnumber = numbers[i]; } END CODE I think this should work, and in the end the variable lowestnumber will hold the lowest value in the ten. Hope this helps.
program to find maximum of two numbers using pointers
choosing a variable to represent one of the unspecified numbers in a problem and using it to write expressions for the other unspecified numbers in the problem.
write an assembly language program to find sum of N numbers
To write a C++ program to display the student details using class and array of object.
see : Write_a_shell_program_using_the_if-the-else_to_test_whether_a_variable_name_is_a_directory_or_a_file
i need this answer
Yes. int a, b; a= 2; b= 3; a= a+b;
12
The required c program is given below /*Swapping(interchange) the two entered numbers*/ #include<stdio.h> main() { /*Without using third variable*/ int a,b,t; printf("Enter a:"); scanf("%d",&a); printf("Enter b:"); scanf("%d",&b); a=a+b; b=a-b; a=a-b; printf("\n After swapping without using third variable"); printf("\na=%d\nb=%d",a,b); }
If you had an array int numbers[10]; you would do it like this: CODE: int lowestnumber = numbers[0]; for(int i = 0; i < 10; i++){ if(numbers[i] < lowestnumber) lowestnumber = numbers[i]; } END CODE I think this should work, and in the end the variable lowestnumber will hold the lowest value in the ten. Hope this helps.
swap (int *a, int *b) { *a ^= *b; *b ^= *a; *a ^= *b; }
Please visit http://talentsealed.blogspot.com/2009/10/to-find-sqaure-of-numbers-using-c.htmlfor the answer.