#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int stack[10],n=0;
int fact(int);
int pop();
void push(int);
main()
{
int num;
printf("\n FACTORIAL USING STACK IMPLEMENTATED WITH ARRAY\n");
printf("\n Enter a number whose factorial is to be found(1-9): ");
scanf("%d",&num);
printf("\n The factorial is : %d",fact(num));
getch();
} void display()
{
int i;
printf("\n The stack is :\n");
for(i=1;i<=n;i++)
{
printf("%d\t",stack[i]);
}
}
int pop()
{ if(n==0)
{
printf("\n Stack empty!Pop not possible!");
exit(1);
}
else
{
int res=stack[n];
--n;
display();
return res;
}
} void push(int x)
{
if(n==9)
{
printf("\n Stack full!Push not possible");
exit(1);
}
else
{
n++;
stack[n]=x;
display();
}
}
int fact(int num)
{
if(num==2)
{
push(2);
push(1);
int res=1;
display();
while(n>=1)
res*=pop();
return res;
} else
{
push(num);
return fact(num-1);
}
}
#!/usr/bin/perl print factorial($ARGV[11]); sub factorial { my($num) = @_; if($num == 1) { return 1; # stop at 1, factorial doesn't multiply times zero } else { return $num * factorial($num - 1); # call factorial function recursively } }
Here is a simple FORTRAN code to calculate the factorial of a given non-negative integer: program factorial implicit none integer :: n, result print *, "Enter a non-negative integer:" read *, n result = 1 if (n < 0) then print *, "Factorial is not defined for negative numbers." else do i = 1, n result = result * i end do print *, "Factorial of", n, "is", result end if end program factorial This program prompts the user for an integer, checks if it's non-negative, and then calculates the factorial using a loop.
factorial number Var num= prompt("enter any number "); Var i=1; Var fact=1; for(i=1;i
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
Functions are used to reduce the lines of code and the complexity of the code. For an instance let us suppose that you want to calculate the factorial of numbers at different times in a program. There are two ways to do this 1. Write a 4-5 line code every time you want to calculate factorial. 2. Write a function of 4-5 lines which calculates the factorial and call that function every time you need to calculate factorial by just writing a single line. In C++ you can pass the variable, address of the variable or a reference to the variable in a function
/*program to calculate factorial of a number*/ #include<stdio.h> #include<conio.h> void main() { long int n; int a=1; clrscr(); printf("enter the number="); scanf("%ld",&n); while(n>0) { a*=n; n--; } printf("the factorial is %ld",a); getch(); }
A flowchart for a program that accepts and displays the factorial of a number would include the following steps: Start, Input the number, Initialize a variable for the factorial, Use a loop to calculate the factorial by multiplying the variable by each integer up to the number, Output the result, and End. Pseudocode for the same program would look like this: START INPUT number factorial = 1 FOR i FROM 1 TO number DO factorial = factorial * i END FOR OUTPUT factorial END
i dn't know. haha
#!/usr/bin/perl print factorial($ARGV[11]); sub factorial { my($num) = @_; if($num == 1) { return 1; # stop at 1, factorial doesn't multiply times zero } else { return $num * factorial($num - 1); # call factorial function recursively } }
Here is a simple FORTRAN code to calculate the factorial of a given non-negative integer: program factorial implicit none integer :: n, result print *, "Enter a non-negative integer:" read *, n result = 1 if (n < 0) then print *, "Factorial is not defined for negative numbers." else do i = 1, n result = result * i end do print *, "Factorial of", n, "is", result end if end program factorial This program prompts the user for an integer, checks if it's non-negative, and then calculates the factorial using a loop.
factorial number Var num= prompt("enter any number "); Var i=1; Var fact=1; for(i=1;i
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(int N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
In Prolog, a simple factorial program can be defined using recursion. Here's a basic implementation: factorial(0, 1). % Base case: factorial of 0 is 1 factorial(N, Result) :- N > 0, N1 is N - 1, factorial(N1, Result1), Result is N * Result1. % Recursive case You can query the factorial of a number by calling factorial(N, Result). where N is the number you want to compute the factorial for.
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.
factorial n is given by formula n! = n.(n-1)....1 int i; long x; x =1; for (i=n;i>1;i--) x = x*i ; will calculate factorial. I have put x as long to avoid integer overflow. checks for n is positive etc. to be added.
First of all we will define what factorial is and how to it is calculated.Factional is non negative integer. Notation would be n! It is calculated by multiplying all integers from 1 to n;For example:5! = 1 x 2 x 3 x 4 x 5 = 120.Note: 0! = 1Small C program that illustrates how factorial might be counted:#include int factorial(int num);int main() {int num;printf("Enter number: ");scanf("%d", &num);printf("Factorial: %d\n", factorial(num));return 0;}int factorial(int num) {if (num == 0) {return 1;}return num * factorial(num - 1);}Testing:Enter number: 5Factorial: 120Enter number: 0Factorial: 1