Write a c program to find sum and average of array elements?

Answer 1

To find the sum and average of array elements in C, you can create a program that initializes an array, calculates the sum of all elements, and then divides the sum by the number of elements to find the average. Here's a simple example:

#include <stdio.h>

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int sum = 0;
    float average;
    int n = sizeof(arr) / sizeof(arr[0]);

    for(int i = 0; i < n; i++) {
        sum += arr[i];
    }

    average = (float)sum / n;

    printf("Sum: %d\n", sum);
    printf("Average: %.2f\n", average);

    return 0;
}

In this program, we first define an array arr, calculate the sum of all elements in the array using a loop, and then find the average by dividing the sum by the number of elements. Finally, we print out the sum and average values.

Answer 2

/*Program in c to to find the sum and average of 1D array*/

#include<stdio.h>

#include<conio.h>

void main()

{

int a[5],i,sum;

float avg=0.0;

printf("Enter the elements of array");

for(i=0;i<5;i++)

scanf("%d" ,&a[i]);

sum=a[0]+a[1]+a[2]+a[3]+a[4];

printf("\n The sum of array is %d " ,sum);

printf("\n The average of array entered is %f ", avg);

getch();

}

Answer 3

Open a computer program like Visual Basic, Java, or C#, and then create an object and label it as an array. Input your 10 numbers into the object, then loop through each object in the array to find the sum, average, and mean by writing code in the program.

Answer 4

In C:

#include <cstdio>

int main()

{

int num, odd, even;

printf("Enter 10 integers: \n");

for(int i = 0; i < 10; i++)

{

scanf("%d", &num);

if(num % 2 0)

{

even++;

}

}

odd = 10 - even;

cout << "Even: " << even << endl;

cout << "Odd: " << odd << endl;

return 0;

}

Answer 5

#include<stdio.h>

int main(){

int i=0,arr[10];

for(i=0;i<5;i++){

scanf("%d",&arr[i]);

}

for(i=0;i<6;i++){

printf("%d \n",arr[i]);

}

printf("\n");

return 0;

}

Answer 6

#include<conio.h>

#include<stdio.h>

void main()

{

float num,avg,sum=0;

int count=1;

clrscr();

printf("Enter ten numbers: \n");

while(count<=10)

{

scanf("%d",&num);

sum+=num;

count++;

}

avg=sum/--count;

printf("\n\nThe sum of the ten numbers = %d",sum);

printf("\nThe average of the ten numbers = %d",avg);

getch();

}

Answer 7

#include

#include

void main()

{

int sum=0,avg=0,a[100],i=0,j=0,k=0;

printf("enter the number of elements wanna add");

scanf("%d",&n);

for(j=0;j<n;j++)

{

k=j+1;

printf("Enter rank %d element element ",k);

scanf("%d",&a[j]);

}

//for sum

for (i=0;i<100;i++)

{

sum=a[i]+sum;

}

printf("sum of nos %d",sum);

for (i=0;i<100;i++)

{

avg=sum/n;

}

printf("avg of nos",avg);

getch();

}

//you can change avg from int to float to get in decimals.

Answer 8

double numbers[10] = { ... };

double sum = 0., mean;

int i;

for (i=0; i<10; i++) sum += numbers[i];

mean = sum / 10.;

Answer 9

#include <stdio.h>

int main (void)

{

int x=3, y=5;

printf ("sum=%d, average=%d\n", x+y, (x+y)/2);

return 0;

}

Answer 10

#include
#include
void main()
{
int i,sum=0;
for(i=1;i<=10;i++)
{
sum=sum+i;
}
printf("%d",sum);
getch();
}