#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,l,m;
clrscr();
for(i=0;i<4;i++)
{
for(j=i+1;j<=4;j++)
{
printf("%d",j);
}
for(k=1;k<=i;k++)
{
printf("%d",k);
}
printf("\n");
for(k=i;k>=1;k--)
{
printf("%d",k);
}
for(j=4;j>=i+1;j--)
{
printf("%d",j);
}
getch();
}
To write a program that inputs a number and displays the digits absent in it, you can follow these steps: Convert the input number into a set of its digits. Create a set of all possible digits (0-9). Subtract the set of digits from the complete set to find the missing ones. Display the missing digits. Here’s a simple example in Python: number = input("Enter a number: ") present_digits = set(number) all_digits = set('0123456789') missing_digits = all_digits - present_digits print("Missing digits:", ''.join(missing_digits))
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
public static void main(String[] args) { int val = 100; int val1 = 50; System.out.println("Number of digits in " + val + " is: " + new String(val + "").length()); System.out.println("Number of digits in " + val1 + " is: " + new String(val1 + "").length()); }
no thanks
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
In decimal we write a number by using a combination of 10 digits (0-9). In base 2, however, numbers are written by using a combination of only 2 digits (0 & 1). We call this number system binary.
#include <stdio.h> int main(int argc, char **argv) { if (argc<1) { printf("Usage: %s number\n",argv[0]); return -1; } int digits=1, i=atoi(argv[1]); while (i/=10) ++digits; printf("%d\n",digits); }
To write the number in digits, you would write it like this: 95,032,659,004.
8,400,000.00
99
Not completely to its end. If you can completely write a number with digits, then it's a rational number.
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
Write the digits in such a way that there are six digits to the right of the number of millions, and three digits to the right of the thousands. Fill out missing digits with zeros.
100,000 your write the number followed by five zeroes
Write a program to convert a 2-digit BCD number into hexadecimal