import java.io.*;
class StringPalindrome
{
static void main()throws IOException
{
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br= new BufferedReader(isr);
System.out.println("Enter a word");
String input=br.readLine();
int x= input.length();
char ans;
String fin="";
for(int y=x-1; y>=0; y--)
{
ans=input.charAt(y);
fin=fin+ans;
}
System.out.println("The reverse is " + fin);
if(fin.equalsIgnoreCase(input))
{
System.out.println("Palindrome");
}
else
{
System.out.println("Not a palindrome");
}
}
}
sdfdg
You don't have to write palindrome programs in wikipedia.
Palindrome number is a number like 121 which remains the same when its digits are reversed. To find this number in a simple java program, just follow the below way. sum = 0; while(n>0) { r=n % 10; sum=concat(r); n=n / 10; } print r;
This program only suits PHP. If you want a proper one try C program for it available on web <body> <?php if(isset($_POST['submit'])) { $text = $_POST['text']; $string = mysql_real_escape_string($text); $invert = strrev($string); if($string == $invert) { echo "<br>Given number is a palindrome!!"; } else { echo "<br>Given number is not a palindrome!!"; } } ?> <form method="post"> <input type="text" name="text" id="text" /> <input type="submit" name="submit" value="Submit" id="submit" onclick="<?php $_SERVER['PHP_SELF']; ?>" /> </form> </body>
what is string
You can do this: <?php if ( $word === strrev( $word ) ) { echo "The word is a palindrome"; } else { echo "The word is not a palindrome"; }
sdfdg
It is a simple program. i think u may understand it :#include#include#includevoid main(){char s[10]=answers.com;char x[10];int a;clrscr();strcpy(x,s);strrev(s);a=strcmp(s,x);if(a==0){printf("the entered string is palindrome");}else{printf("the entered string is not palindrome");}output:given string is not palindrome
You don't have to write palindrome programs in wikipedia.
Write your program and if you are having a problem post it here with a description of the problem you are having. What you are asking is for someone to do your homework for you.
Palindrome number is a number like 121 which remains the same when its digits are reversed. To find this number in a simple java program, just follow the below way. sum = 0; while(n>0) { r=n % 10; sum=concat(r); n=n / 10; } print r;
int pallindrom(int p){ /*write all logic*/ }
This program only suits PHP. If you want a proper one try C program for it available on web <body> <?php if(isset($_POST['submit'])) { $text = $_POST['text']; $string = mysql_real_escape_string($text); $invert = strrev($string); if($string == $invert) { echo "<br>Given number is a palindrome!!"; } else { echo "<br>Given number is not a palindrome!!"; } } ?> <form method="post"> <input type="text" name="text" id="text" /> <input type="submit" name="submit" value="Submit" id="submit" onclick="<?php $_SERVER['PHP_SELF']; ?>" /> </form> </body>
Copy and reverse the string. If the reversed string is equal to the original string, the string is a palindrome, otherwise it is not. When working with strings that hold natural language phrases (including punctuation, whitespace and so on) we must remove all the non-alphanumerics and convert the remainder to a common case, such as lower-case, prior to copying and reversing the string.
If you want to check whether a string is a palindrome, you can reverse the string (for example, the Java class StringBuffer has a reverse() method), and then compare whether the two strings - the original string and the reverted string - are equal. Alternately, you could write a loop that checks whether the first character of the string is equal to the last one, the second is equal to the second-last one, etc.; that is, you have a counter variable (in a "for" loop) that goes from zero to length - 1 (call it "i"), and compare character #i with character #(length-i-1) inside the loop.
what is string
i dont no string for servlate