Write a program that inputs four digits numbers like 1234 from user and then display it in reverse order in c?

Answer 1

#include<stdio.h>

main()

{

int i,j,k,n;

printf("Enter the number of lines");

scanf("%d",&n);

for(i=n;i>=0;i--)

{

for(k=n-i;k>0;k--)

{

printf(" ");

}

for(j=i-1;j>=0;j--)

{

printf("%2d",i);

}

printf("\n");

}

}

Answer 2

The following example shows one possible solution.

Example code:

#include

int main()

{

using namespace std;

int x = 0;

bool bRepeat = true;

while( bRepeat )

{

cout << "Enter a 4 digit number:\t";

if( bRepeat = (!( cin >> x ) x < 1000 x > 9999 ))

{

cin.clear();

cin.ignore(numeric_limits::max(), '\n');

cout << "Not a valid 4 digit number. Try again.\n" << endl;

}

}

cout << x << " in reverse is:\t";

while( x )

{

cout << x % 10;

x /= 10;

}

cout << endl;

return(0);

}

Example output:

Enter a 4 digit number: 12345

Not a valid 4 digit number. Try again.

Enter a 4 digit number: abcd

Not a valid 4 digit number. Try again.

Enter a 4 digit number: 1234

1234 in reverse is: 4321

Answer 3

Check this link

http://www.mycplus.com/featured-articles/print-pyramids-and-diamonds-in-c-language/