To check for divisibility, use the modulus, or % operator. If the expression results in zero, then the first number is divisible by the second number. For example, 10%5 equals 0 because 10 is divisible by 5. When the expression does not result in 0, the number is not divisible(10%7=3, so 10 is not divisible by 7).
Reference:http:cprogramming-bd.com/c_page2.aspx# strange number
The generation of palindromic numbers within a given range is best done with a computer program. Space it limited so an example of program code cannot be shown here, but the Codecast website gives full guidance.
Write a program to find the number and sum of all integers from 100 to 300 that are divisible by 11
#include #include#define N 100 /* change the upper limit by changing value of N */int main(){int i;clrscr();printf("\nPROGRAM TO PRINT NUMBERS DIVISIBLE BY 8 between 1 and 100\n");for(i=1;i
Here's a simple Java program that uses a for loop to generate the first 10 multiples of the first 10 natural numbers: public class Multiples { public static void main(String[] args) { for (int i = 1; i <= 10; i++) { System.out.print("Multiples of " + i + ": "); for (int j = 1; j <= 10; j++) { System.out.print(i * j + " "); } System.out.println(); } } } This program iterates through the first 10 natural numbers and prints their multiples from 1 to 10.
(rand()&50+1)*2
2,3,5,7,9,11,13,17,19,23,29,31,37,39,41,43,47,49
There are several shell programs available for download on the Internet that will generate prime numbers. The best way to find a prime number is through calculation, however.
write a c program to accept a number and generate a square root cube and exponential values
VBnet program to find the prime numbers between 100 to 200?
/* a number divisible by x should be a multiple of x */ int i, n,x; scanf ("%d", &n); scanf ("%d",&x); for(i=x;i =< n;i+=x) { printf ("%d", x); }
not sure of the exact syntax but its quite hard to generate them, but you can go through a list of numbers, that could be 0-10000000 say, and check if it is prime by dividing it by all the numbers that are smaller than it
Reference:http:cprogramming-bd.com/c_page2.aspx# strange number
The generation of palindromic numbers within a given range is best done with a computer program. Space it limited so an example of program code cannot be shown here, but the Codecast website gives full guidance.
You can use int i; for (i = 10; i <= 50; i += 2) {//print i} as a program to print even numbers between 10 and 50.
#include<stdio.h> #include<conio.h> void main() { clrscr(); for (int i=1;i<=100;i++) { if(i%2 !=0 && i%3 !=0) { printf("\n Numbers that are not divisible by 2 or 3:%d \n ",i); } printf("\n"); } getch(); }
The numbers divisible by all five numbers must be multiples of the LCM (LCD) of the numbers, which is 22 x 3 x 5 = 60. There are 5 numbers: 240, 300, 360, 420, and 480. --- There is also a C program that can be used to find these: #include <stdio.h> void main() { for (int i=200;i<=500;++i) if (!((i%6)(i%4)(i%5)(i%3)(i%2))) printf("%d ",i); printf("\n"); }