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(a + b) * c / ((x - y) * z)

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Q: Convert infix to prefix to postfix?
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Why you need convert a expression into postfix expression?

You convert an (infix) expression into a postfix expression as part of the process of generating code to evaluate that expression.


Who invented postfix and infix?

infix: old Egyptians/Assirs some thousands year before prefix: Jan Łukasiewicz (Polish Notation) postfix: Burks, Warren, and Wright (Reverse Polish Notation)


Which data structure is needed to convert infix notations to post fix notations?

stack is the basic data structure needed to convert infix notation to postfix


What is prefix expression?

Example: prefix: * 2 + 3 4 infix: 2 * (3+4) postfix: 2 3 4 + *


How to convert prefix to postfix?

convert to perfixed to postfixed


Which data structure convert logical to physical address?

Linear data structure is used to convert the logical address to physical address .Stack is used in this and the various conversion such as postfix,prefix and infix notation are come in this


Why do compilers convert infix expressions to postfix?

people almost exclusively use infix notation to write mathematical expressions, computer languages almost exclusively allow programmers to use infix notation. However, if a compiler allowed infix expressions into the binary code used in the compiled version of a program, the resulting code would be larger than needed and very inefficient. Because of this, compilers convert infix expressions into postfix notation expressions, which have a much simpler set of rules for expression evaluation. Postfix notation gets its name from the fact that operators in a postfix expression follow the operands that they specify an operation on. Here are some examples of equivalent infix and postfix expressions Infix Notation Postfix Notation 2 + 3 2 3 + 2 + 3 * 6 3 6 * 2 + (2 + 3) * 6 2 3 + 6 * A / (B * C) + D * E - A - C A B C * / D E * + A C * - Where as infix notation expressions need a long list or rules for evaluation, postfix expressions need very few.


How do you convert infix to postfix without using data structures?

Without data-structures you cannot even store expressions, let alone convert or evaluate them.


Program to convert infix to prefix?

I dont have the idea about the program but I know that prefix means the first starting letters of a particular things. I really think so there is a progam to convert infix to prefix but i might have misunderstood your question can you make it little simpler please.


Postfix to Infix java?

A postfix incrementation or decrementation is handled by the ++ and -- operators. Postfix specifically refers to adding the operator after the variable name (eg. i++). This will attempt to increase/decrease the data type by 1. It differs from prefix in that it will return the variable before the calculation.Example:int i = 1;System.out.print(i++); //1System.out.print(i); //2


Example program of how to convert infix notation to postfix notation and prefix notation?

/**************************//**********cReDo**********//*****mchinmay@live.com***///C PROGRAM TO CONVERT GIVEN VALID INFIX EXPRESSION INTO POSTFIX EXPRESSION USING STACKS.#include#include#include#define MAX 20char stack[MAX];int top=-1;char pop();void push(char item);int prcd(char symbol){switch(symbol){case '+':case '-':return 2;break;case '*':case '/':return 4;break;case '^':case '$':return 6;break;case '(':case ')':case '#':return 1;break;}}int isoperator(char symbol){switch(symbol){case '+':case '-':case '*':case '/':case '^':case '$':case '(':case ')':return 1;break;default:return 0;}}void convertip(char infix[],char postfix[]){int i,symbol,j=0;stack[++top]='#';for(i=0;iprcd(stack[top]))push(symbol);else{while(prcd(symbol)


Write an algorithm in c to convert an infix expression to a postfix expressionexecute your algorithm with the following infix expression as your input. m nk pgh a bc?

An algorithm can not be written with the following infix expression without knowing what the expression is. Once this information is included a person will be able to know how to write the algorithm.