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If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?

Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.


What does a Punnett Square do for geneticists?

Punnett Squares are useful because they allow you to see the chance of what genes will be handed down to the offspring. They are a quick and easy way to determine the chance of a offspring having a certain characteristic


What are the genotypes of offspring from an FF X ff cross?

The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.


What is the phenotype of a offspring?

The phenotype of an offspring refers to its observable traits or characteristics, such as physical appearance, behavior, or other traits resulting from interactions between genes and the environment. These traits can include things like eye color, height, or susceptibility to certain diseases.


Freckles are a dominant characteristic The appearance of freckles is the phenotype what represents a heterozygous genotype for freckles?

If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.


What is the probability that an offspring mouse will be born with the genotype ff ee?

To determine the probability of an offspring mouse being born with the genotype ff ee, you need to know the genotypes of the parent mice. If both parents are heterozygous (Ff Ee), the probability of producing ff offspring is 1/4 and for ee offspring is also 1/4. To find the probability of the combined genotype ff ee, you multiply these probabilities: (1/4) x (1/4) = 1/16. Thus, there is a 1/16 probability that an offspring mouse will have the genotype ff ee, assuming both parents are Ff Ee.


If the dominant allele F produces yellow flower color and re recessive allele f produces white flower color what are the possible pairs of alleles that would produce the yellow-flower phenotype?

The possible pairs of alleles that would produce the yellow-flower phenotype are FF and Ff. Since the F allele is dominant over f, having at least one F allele in the genotype will result in a yellow flower color.


If feather color in parrots is made by 1 autosomal gene with 2 alleles F and f The F is blue and f is yellow F allele shows imcomplete dominance over f allele 2 heterozygous Ff green parrots bred?

First, to restate the question in a more comprehensible form:Feather colour in parrots is determined by a single autosomal gene. The gene has two alleles, F and f. F causes blue feather colour and f causes yellow feather colour. F shows incomplete dominance over f (i.e, a heterozygote has a mixed phenotype, green feathers). If two green parrots, genotype Ff breed, what colour will the offspring be?This is a basic Mendelian cross. A similar example, with Punnet square, can be seen in the Wikipedia page for 'Mendelian inheritance', Figure 3. This page is a good starting point for understanding the principles involved.To directly answer the question, 25% of the offspring will be blue (FF), 25% yellow (ff) and 50% green (Ff).


In certain rats black fur is dominant over white fur If two rats both heterozygous for fur color are mated their offspring would be expected to have?

There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur


Will the offspring have cystic fibrosis if the mother is FF and father is Ff?

No. Cystic fibrosis is an autosomal recessive disease. Each parent would have to be a carrier of a CF mutation and would be Cc.


What is the broadcast MAC address in hexadecimal notation?

FF-FF-FF-FF-FF-FF


How can phenotypes be used to predict genotypes in a pedigree?

Phenotype is physical appearance of a character in a living being which depends on their genotype i.e. genetic constituents so by study of phenotype, genotype can be predicted which may or may not be exactly same but definately not wrong because every character can be homozygously dominant or hetrozygously dominant.