When a true-breeding tall plant (TT) is crossed with a true-breeding short plant (tt), all the offspring in the first generation (F1) will be heterozygous (Tt) and exhibit the tall phenotype, as tall (T) is dominant over short (t). Therefore, the phenotypic ratio of the offspring will be 100% tall. If these F1 plants are then crossed with each other (Tt x Tt), the resulting phenotypic ratio in the second generation (F2) will be 3 tall (TT or Tt) to 1 short (tt).
The ratio produced if Tt is crossed with tt is 1:1 for the genotype and 1:1 for the phenotype. This is because all the offspring will inherit a recessive allele from the tt parent, resulting in all of them having the same genotype and phenotype.
The ratio produced would be 1:1 for heterozygous (Tt) offspring to homozygous recessive (tt) offspring. This is because the parent with genotype Tt will pass on one dominant allele (T) and one recessive allele (t) to its offspring, resulting in a 50% chance of either genotype in the offspring.
3 : 1 ( since the given situation of segregating genotypes TT Tt Tt tt comes under monohybrid genetic combination, it will show 3 tall plants and 1 dwarf plant because gene T is dominant over t.
yes becasue the color changes and it doset mean it's not almost exactly the same as a black or even a purple fly when its crossed with another fly you get (tt) (TT) (tT) AND (Tt)
genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers
In Mendel's F2 generation, the 3:1 ratio observed for dominant to recessive traits arises from the segregation of alleles during gamete formation. When he crossed heterozygous parents (Tt), the resulting offspring can inherit combinations of alleles that produce three dominant phenotype offspring (TT or Tt) and one recessive phenotype offspring (tt). This reflects the principles of Mendelian inheritance, specifically the law of segregation, where each parent contributes one allele for a trait, leading to the 3:1 phenotypic ratio in the F2 generation.
75% there will be TT, Tt, Tt, and tt. tt is going to be short. This means that 3/4 will be tall. 3/4 is 75%
Tt, tt -- novanet :)
The possible offspring outcomes of this cross would be 50% Tt (heterozygous) and 50% tt (homozygous recessive).
In the offspring generation from crossing two pea plants with TT genotypes, all the offspring will have the genotype Tt. However, all of these offspring will be tall since the tall trait is dominant (T) over the short trait (t). Therefore, there will be no short tt plants in the new generation.
rather TT Tt tt
TT Tt tt