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If Dick could stuff envelopes working alone for six hours and Jane could stuff them all in four hours how long would it take them working toghether?
Wiki User
∙ 14y ago
D's rate = x/6 envelopes per hour
J's rate = x/4 "
together x = (x/6 +x/4) * Time
rewritten: x = (4x/24 + 6x/24) * time
again: x = 10x/24*Time
again: 24x = 10x*Time
again: 24/10 = Time
ergo: 2.4 hours (or 144 minutes) <<<< answer
Wiki User
∙ 14y ago
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If Dick could stuff six envelopes working alone for six hours and Jane could stuff them all in four hours how long would it take them working toghether?
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