3
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As it is a split, it could mean that one business partner gets three quarters, while the other partner gets only one quarter. (I assume on net profits? Without more info. in the question, I can't be more specific.)
This actually sounds like a "reverse stock split." In such a transaction, which is done to increase the stock price without changing the company's market cap, a company trading three million shares at $10 who did a 1:3 reverse stock split would finish the day trading 1 million shares at $30. The other way is the "stock split," which is done to get the stock price down, one share at $30 becomes three shares at $10.
Your answer would be 1,176 square feet ...here's how. Your equation is 1/3 (length x width x height) 1/3 (12 x 3.5 x 7) 1/3 (3,528) 1,176 square feet Hope this helped you out! Good luck.
7 or 4 maybe 1 7 or 4 maybe 1
5 - 4 = 1 = 3^0 8 - 5 = 3 = 3^1 17 - 8 = 9 = 3^2 44-17 = 27 = 3^3 X - 44 = 3^4 = 81 X = 125
Return on Assets = Profit Margin on Sales x Asset Turnover .1 = Profit Margin on Sales x 3 .033 = Profit Margin on Sales
33.3 percent in 3 to 1 split 25 percent in 4 to 1 split
24 = 2 x 2 x 2 x 3
3 x 25 5 x 15
4
(x^3 + 2x^2 + 3x - 6)/(x - 1) add and subtract x^2, and write -6 as (- 3) + (-3) = (x^3 - x^2 + x^2 + 2x^2 - 3 + 3x - 3)/(x - 1) = [(x^3 - x^2) + (3x^2 - 3) + (3x - 3)]/(x - 1) = [x^2(x - 1) + 3(x^2 - 1) + 3(x - 1)]/(x - 1) = [x^2(x - 1) + 3(x - 1)(x + 1) + 3(x - 1)]/(x - 1) = [(x - 1)(x^2 + 3x + 3 + 3)]/(x - 1) = x^2 + 3x + 6
It is 123.99
I like back into multidimensional space where were born to be sleeping forever thousands autumn. Pierre De Fermat's last theorem. The conditions. x,y,z,n are the integers >0 and n>2. z^n=/x^n+y^n. Assumptions z^3=x^3+y^3. Therefore z=(x^3+y^3)^1/3. I define . F(x,y)=(x^3+y^3}^1/3 - [ (x-x-1)^3+(y-x-1)^3]^1/3. Therefore [z-F(x,y)]^3={ (x^3+y^3)^1/3 - (x^3+y^3}^1/3 + [ (x-x-1)^3+(y-x-1)^3] ^1/3 }^3={ [(x-x-1)^3+(y-x-1)^3]^1/3 }^3 =(x-x-1)^3+(y-x-1)^3= (y-x-1)^3-1. Because [z-F(x,y)]^3=(y-x-1)^3-1 . Attention [(y-x-1)^3-1 ] is an integer , [(y-x-1)^3-1 ]^1/3 is an irrational number therefore [(y-x-1)^3-1 ]^2/3 is an irrational number too. Example (2^3-1) is an integer , (2^3-1)^1/3 is an irrational number and (2^3-1)^2/3 is an irrational number too. Because z-F(x,y)=[y-x-1)^3-1]^1/3. Therefore z=F(x,y)+[(y-x-1)^3-1] ^1/3. Therefore z^3=[F(x,y)]^3.+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+3F(x,y)*[(y-x-1)-1]^2/3+[(y-x-1)^3-1]. Therefore 3F(x,y)*[(y-x-1)^3-1]^2/3+[F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3 =0 Because. z-F(x,y)=[ (y-x-1)^3-1]^1/3. Therefore F(x,y)=z - [(y-x-1)^3-1]^1/3. Therefore 3F(x,y)*[(y-x-1)^3-1]^2/3 =3z*[(y-x-1)^3-1]^2/3 -3[(y-x-1)^3-1]. Therefore. 3z*[(y-x-1)^3-1]^2/3 - 3[(y-x-1)^3-1]+[F(x,y)]^3+3[F(x,y)]^2*[y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3=0.. Named [F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3= W. We have 3z*[(y-x-1)^3-1]^2/3 is an irrational number because z is an integer and had proved [(y-x-1)^3-1]^2/3 is an irrational number. And 3[(y-x-1)^3-1] is an integer because x,y are the integers. And 3z*[(y-x-1)^3-1]^2/3 - 3[(y-x-1)^3-1]+[F(x,y)]^3+W=0. Therefore an irrational number - an integer+W=0. Therefore W is an complex irrational number. Named 3z*[(y-x-1)^3-1]^2/3 is 3z*B And Named 3[(y-x-1)^3-1] is C . Therefore 3z*B - C +W=0. Therefore 3z*B=C-W. Because z is an integer. B is an irrational number=[(y-x-1)^3-1]^2/3 Attention (an integer)^2/3 and (an integer)^2/3 is an irrational number. W is an complex irrational number. C is an integer. Therefore. an integer*an irrational number=an complex irrational number + an integer. Unreasonable. Therefore. z^3=/x^3+y^3 Similar z^n=/x^n+y^n. ISHTAR.
You go to multiplayer then you go to split screen then turn on second controller then press x then turn on third controller then press x
There is some ambiguity in the question because of the absence of brackets. For example, is it 1/x + 3 ... or 1/(x+3) ... ? So, this is my interpretation of the question. If it is not what you meant please resubmit using brackets. 1/(x+3) + 1/1/(x-3) = 1/(x+3) + (x - 3) = (1 + x2 - 9)/(x + 3) = (x2 - 8)/(x + 3)
1/3 x 1/3 x 1/3 x 1/3 =1/81
It is probably best to split up the formula: For example, if X represents the outcome of a single roll of a fair die, then Prob(X = 1) = 1/6 Prob(X = 2) = 1/6 Prob X > 2) = 4/6 = 2/3
1/3% = (1/3) x 1% = 1/3 x 0.011/3 x 0.01 x 1,500 = 1/3 x 15 = 5