.65*.65*.65=.274625 or if you have to turn it into a percent it is 27%. How I got that is I rounded it by its nearest hundredth.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
The individual probability that a child born will be female is 50% or 0.5.Using this we can calculate the probability that at least one of the children will be female by:calculating the probability that none of the children will be female and then subtracting this from 1.The probability that all the children are male is therefore 0.53 = 0.5 * 0.5 * 0.5 = 0.125.Thus the answer is 1 - 0.125 = 0.875 = 87.5%
In a family with four children, the probability of having four boys is 1 in 16.
The probability that a child is affected with galactosemia is 1/40,000. The probability that both children are affected would be (1/40,000) * (1/40,000) = 1/1,600,000,000.
Most children of any age seem not to like vegetables. I must have been a very boring child, I generally liked vegetables.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of 3 girls out of 4 children is 0.2331
3M with the help of a nationwide Children's Hospital Association.
3M with the help of a nationwide Children's Hospital Association.
1 in 64
To determine the probability of selecting a family with exactly 3 male children out of 4, we can use the binomial probability formula. The probability of having a male child is typically considered to be 0.5 (assuming an equal likelihood of male and female). The probability of exactly 3 males in 4 children is calculated as ( P(X = 3) = \binom{4}{3} (0.5)^3 (0.5)^1 = 4 \times 0.125 \times 0.5 = 0.25 ). Thus, the probability is 0.25 or 25%.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability that all three children are boys is approx 0.1381
Since the probability of having a son is about 1/2, the probability of the first 4 children being boys is about (1/2)4.