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Galactosemia is a recessive human disease A woman and her husband are both heterozygous for the glactosemia gene She has identical twins What is the probability that they are both girls and have ga?
The probability both twins are girls is 0.25 (0.5 * 0.5). Each girl will inherit half of the mother's genes, so there is a 0.25 chance they both inherit the galactosemia gene from their heterozygous mother. Therefore, the probability that they are both girls and have galactosemia is 0.25 * 0.25 = 0.0625 or 6.25%.
Do both parents have to be a carrier of galactosemia for the child to be a carrier?
No, if one parent is a carrier of galactosemia and the other parent is not, the child has a 50% chance of being a carrier as well. It only requires one parent to pass on the gene for the child to be a carrier.
What do galactosemia and tay-sachs disease have in common?
Both galactosemia and Tay-Sachs disease are genetic disorders caused by the absence or dysfunction of a particular enzyme. Galactosemia is a disorder where the body is unable to break down galactose, a sugar found in milk, while Tay-Sachs disease is a disorder where the body lacks an enzyme needed to break down certain lipids in the brain. Both conditions can lead to serious health complications if not managed properly.
What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
How do you know if a gene is X- linked?
X linked diseases when recessive are only present in female children when both parents have the disease. If the mother is only a carrier of the disease then each male child would have a 50% probability of having the disease, but no female children would be affected (50% would be carriers). Hemophilia is an example of a recessive X linked genetic defect: http://www.answers.com/main/ntquery?s=hemophilia&gwp=13
Galactosemia is a recessive human disease A woman and her husband are both heterozygous for the glactosemia gene She has identical twins What is the probability that they are both girls and have ga?
The probability both twins are girls is 0.25 (0.5 * 0.5). Each girl will inherit half of the mother's genes, so there is a 0.25 chance they both inherit the galactosemia gene from their heterozygous mother. Therefore, the probability that they are both girls and have galactosemia is 0.25 * 0.25 = 0.0625 or 6.25%.
What do galactosemia ansd Tay-Sachs disease have in common?
Both are inherited (genetic) disorders
What is the probability that a family will have a boy?
The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
What causes galactosemia II?
Galactosemia II is caused by defects in both copies of the gene that codes for an enzyme called galactokinase (GALK). The frequency of occurrence of galactosemia II is about one in 100,000-155,000 births.
What is the probability that a family of 4 would have a girl first and a girl last?
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. A family of 4 is a family of two parents and two children. The probability that both children are girls is 0.2334
At least one child in a family with two children is a boy the the probability that both children are boys?
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
What do experimental probability and theoretical probability have in common?
They are both measures of probability.
Do both parents have to be a carrier of galactosemia for the child to be a carrier?
No, if one parent is a carrier of galactosemia and the other parent is not, the child has a 50% chance of being a carrier as well. It only requires one parent to pass on the gene for the child to be a carrier.
What do galactosemia and tay-sachs disease have in common?
Both galactosemia and Tay-Sachs disease are genetic disorders caused by the absence or dysfunction of a particular enzyme. Galactosemia is a disorder where the body is unable to break down galactose, a sugar found in milk, while Tay-Sachs disease is a disorder where the body lacks an enzyme needed to break down certain lipids in the brain. Both conditions can lead to serious health complications if not managed properly.
If both parents have the gene for polydactyly with 4 children how many of the children will have extra toes or fingers?
1-2 children will be affected causing long life disability.
If two events are independent the probability that both occur is?
That probability is the product of the probabilities of the two individual events; for example, if event A has a probability of 50% and event B has a probability of 10%, the probability that both events will happen is 50% x 10% = 5%.
The probability that Bob will win a game of snooker is 0.7 and the probability that he will win a game of chess is 0.6 What is the probability that he will not win both games?
The probability that he will not win both games is 0.58
