If you mean pure substances then:
HCl(aq) and NaCl(aq) are not pure substances but solutions. The (aq) means the substance is dissolved in water.
HCl(g) and NaCl(s) is are pure substances
yes. sodium bicarb is a base. It reacts with HCl in the presence of water to make CO2, NaCl, and water
The net ionic equation for the reaction between sodium and hydrochloric acid (HCl) is: 2Na(s) + 2HCl(aq) -> 2NaCl(aq) + H2(g)
Na2S2O3(aq) + 2HCL(aq) => 2NaCl(aq) + S(s) + SO2(g) + H2O(l)
Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!
The reaction equation between NH4Cl (ammonium chloride) and NaOH (sodium hydroxide) is NH4Cl + NaOH → NaCl + NH3 + H2O. This is a neutralization reaction where the products are sodium chloride (table salt), ammonia gas, and water.
The ionic equation for HCl and KHCO3 is H+(aq) + Cl-(aq) + K+(aq) + HCO3-(aq) → KCl(aq) + H2O(l) + CO2(g). The net ionic equation is H+(aq) + HCO3-(aq) → H2O(l) + CO2(g).
Na2S(aq) + ZnCl2(aq) --> 2NaCl(aq) + ZnS(s)
an arrhenius acid solution has H+ ions, while arrhenius base has OH- ions when they are mixed they make WATER ANS SALT Which chemical equation represents the reaction of an Arrhenius acid and an Arrhenius base? (1) HC2H3O2(aq) + NaOH(aq) --> NaC2H3O2(aq) + H2O(l) (2) C3H8(g) + 5 O2(g)--> 3 CO2(g) + 4 H2O(l) (3) Zn(s) + 2 HCl(aq)--> ZnCl2(aq) + H2(g) (4) BaCl2(aq) + Na2SO4(aq) --> BaSO4(s) + 2 NaCl(aq) the answer for this example is 1 since its the only one that has water and NaC2H3o2(aq) is a salt
you can prepare sodium chloride by mixing hydrochloric acid with sodium hydroxide solution. 1. Get the correct amount of hydrochloric acid and sodium hydroxide through titration (neutralisation reaction) 2. Obtain crystals of the salt by crystallisation 3. Obtain pure salt crystals by recrystallisation 4. Mrs hood is fat another way of preparing sodium chloride is Sodium chloride will be synthesized by reacting sodium bicarbonate with hydrochloric acid. The reaction equation is shown below: NaHCO3+ HCl (aq) → NaCl (aq) + H2O (aq) + CO2
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
Yes, after reaction: Bas + 2 H+aq + 2Cl-aq --> Ba2+aq + H2(g) + 2 Cl-aq
The standard enthalpy of formation, ΔH°f, for HCl(g) is -92.31 kJ/mol. The enthalpy change for the reaction in which HCl(g) is dissolved in water to form HCl(aq) is known as the enthalpy of solution of HCl, and is approximately -74.8 kJ/mol.