This concentration is 9 g/L.
A person is dehydrated and is given 500 ml of normal saline.how many grams of sodium chloride will person recieve ?
Normal saline is 0.9% NaCl (sodium chloride or salt). This means that for every 100 mL of water there is 0.9 grams of NaCl. This is equivalent to 9.0 grams per litre or 0.009 grams per millilitre.
Normal saline (0.9% NaCl) has a concentration of 154 milliequivalents per liter of sodium. This means that a 1L bag of normal saline would contain 154 milliequivalents of sodium.
The answer is 8 g NaCl.
The answer is 648,68 g.
The answer is 0,96 moles.
There are approximately 20 drops in 1 ml of normal saline.
540 g NaCl is equal to 0,54 kg.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl
The molar mass of NaCl is approximately 58.44 g/mol. Therefore, two moles of NaCl would be 2 * 58.44 = 116.88 grams.
The mass is 0,324 g.