250 g sodium chloride contain 99,16 g sodium.
Two moles of sodium chloride is equivalent to 116,88 (rounded) g.The molar mass of NaCl 58.5 grams per mole. 117 grams of salt is equivalent to two moles. Dissolve this much of salt in exactly 1L of distilled water in a volumetric flask to prepare 2M NaCl.
Well, isn't that a happy little question! In a 1000ml bag of Sodium chloride 0.9%, there is 9 grams of sodium chloride. It's like adding a touch of seasoning to your painting to make it just right!
There is no chlorine present in NaCl (sodium chloride). Sodium chloride is made up of sodium ions (Na+) and chloride ions (Cl-), but the element chlorine itself is not present in its elemental form in NaCl.
The formula unit of sodium chloride (NaCl) contain 60,33 % chlorine.
Normal saline is 0.9% weight/volume sodium chloride to water. This is 9 grams per litre. NaCl has a molecular weight of 58.5, sodium (Na) has a weight of 23, which is 39.3% of the molecular weight. So sodium is 39.3% of the weight. 1 litre of saline has 9 grams, 250ml is a quarter of a litre, so has 9/4 grams = 2.25 grams. 39.3% of 2.25 g is 0.884 grams of sodium.
Sodium content in sodium is approximately 393 mg per 100 grams.
58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-
In order to determine this, it is necessary to know what solution we are looking at. One we know that we can look at the grams in a mole of the substance and determine the percentages based on molecular weight.
2 grams of salt = 2,000 mg of sodium
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
The answer to the question is 120 grams of water :)
Sodium chloride has two atoms in the formula unit.