This a saline solution with the concentration of 0,9 g NaCl/100 mL distilled water. This is a isotonic solution; the meaning is that the osmotic pressure of the this solution is equal to the osmotic pressure of the blood serum.
NaCl is the formula unit of sodium chloride; 0,9 NaCl is a solution, probable o,9 molar.
Well .9 in a % would be 90%, and .09 would be 9%. So I would say yes.
9%
A solution with a concentration of NaCl higher than 9 g/L is hypertonic.
Because you asked how to make a 9 g/L solution of NaCl rather than a 9.0 g/L, or a 9.00 g/L solution, to make a 9 g/L solution of NaCl you first weigh out 9 g of dry NaCl. The weight, actually mass, of the NaCl needs to be 9 g plus or minus 1 g. Next, add the 9 g of NaCl to less than one liter of water, perhaps 25 or 50 mL less. Stir or shake the flask very well for several minutes after all of the NaCl has dissolved, then bring the total volume up to nearly 1 L. Stir or shake the flask very well again, then add water if necessary to ensure that the total volume is one liter.
The concentration of NaCl in the solution is 9 parts per million (ppm), which is equivalent to 9 mg/L (milligrams per liter). This concentration indicates a very dilute solution of NaCl.
This is a isotonic solution of NaCl (9 g/L) containing also dextrose (50 g/L).
This concentration is 9 g/L.
9 g/L NaCl = 0,9 g/100 mL = 0,154 moles/L = 300 mOsm/L
Not exactly. Saline solution is sterilized and is a dilution of sodium chloride (NaCl) - meaning that the NaCl is dissolved in deionized water. The solution is 9 grams of sodium chloride (NaCl) dissolved in 1 liter of water.
how do open a plastic bottle of liquid Nacl 9% to clean my incision
1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl