1 mol/L sodium chloride is equal to 2 osmol/L.
NaCl is generally added to the nutrient media for maintaining the Osmotic pressure. Maintaining osmotic pressure is important, because, increase or decrease in the osmotic pressure leads to cell burst or death due to the effect of osmosis. So, maintaining the osmotic pressure is done by adding correct amount of NaCl.
NaCl--table salt--is typically look at as the solid solute within a solution. The osmotic pressure you need is for the solvent which will need to be calculated I believe. The Van Hoff Factor for NaCl (1.9) is probably what you needed
The solution of NaCl with the concentration 0,9 % is considered normal saline; the osmotic pressure is equal to the pressure in the cells.
This a saline solution with the concentration of 0,9 g NaCl/100 mL distilled water. This is a isotonic solution; the meaning is that the osmotic pressure of the this solution is equal to the osmotic pressure of the blood serum.
The greater osmotic pressure will be observed with 3.60 g of NaCl in 351.2 ml of water. This is because NaCl dissociates into two ions (Na+ and Cl-) in solution, contributing more particles that will contribute to osmotic pressure, compared to glucose which does not dissociate.
Osmotic pressure of saline (0.91% NaCl w/v) is arround 0.0085 ATM.The osmotic pressure is 7.58 ATM at 25 °C. P=MRT The molarity of 0.9% NaCl is 0.155M. But it has 2 ions per formula so 0.31 mol/L * 0.082 latm/Kmol * 298K= 7.58 ATM
The osmotic coefficient of sodium chloride is 0,93.
Seven seas
CaCl2. Because it breaks down into 3 particles , 1 Ca and 2 Cl. "i" for CaCl2 is 3 While NaCl breaks down to only 2 particles Water and C6H12O6 do not break down at all, they remain as single particles.
Nothing. NaCl creates a reverse reaction to H2O.
In a solution with a difference in osmotic pressure, water moves from an area of low osmotic pressure to an area of high osmotic pressure.
NaOH(hydroxide) + HCl(acid) ---------> NaCl(salt) + H2O(water)