These substances doesn't react.
The Cu2+ from CuSO4 is displaced by the Na+ from NaCl and CuCl2 and Na2SO4 are formed.
AgNO3(aq) + NaCl(aq) --> AgCl(s) + NaNO3(aq)
When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.
When CaCl2 reacts with NaHCO3, the products formed are CaCO3 (calcium carbonate), NaCl (sodium chloride), and H2O (water).
The substances formed after a reaction are called products.
Dissociation products of sodium chloride are the cation Na+ and the anion Cl-.
Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:2K + CuSO4 --> K2SO4 + Cu
You get a sodium sulfate deposit.
The products of the reaction are sodium chloride (NaCl) and water (H2O) formed through the combination of hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
C12H22O11 is the Disaccharide Sucrose (table sugar). The other three are salts.
The chemical equation for the reaction between copper(II) sulfate (CuSO4) and sodium hydroxide (NaOH) is CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4. In this reaction, copper(II) hydroxide and sodium sulfate are formed as products.