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Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:

2K + CuSO4 --> K2SO4 + Cu

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12y ago

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Related Questions

What products are formed from CuSO4 and NaCl?

These substances doesn't react.


What is formed by CuSO4 plus HCl?

When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.


Is CuSO4 hygroscopic?

Yes, white CuSO4 can absorb 1 to 5 molecules of H2O (mono- and penta-hydrates (blue) are formed).


Is there an ion exchange when you add CuSO4 to NaCl?

The Cu2+ from CuSO4 is displaced by the Na+ from NaCl and CuCl2 and Na2SO4 are formed.


What is the sedimentary rock called that ks formed by mud and clay?

it is called SHALE :)


What is the insoluable product of the reaction KOH plus CuSO4 and how do you find it?

The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.


What is the balanced equation for CuSO4?

CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.


What is formed when copper is added to dilute sulphuric acid?

cu + H2so4 --->cuso4+2H two molecules of hydrogen evolves........


Do a 5m cuso4 and 5m cuso4 5 h2o contain the same quantities of cuso4?

Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.


Is CuSO4 an electrolyte?

Yes, CuSO4 is an electrolyte.


What colour will be formed when HNO3 and CUSO4 react?

Nitric acid (HNO3) and copper(II) sulfate (CuSO4) will react in a double replacement reaction to produce copper(II) nitrate and sulfuric acid. The correctly balanced equation is: 2HNO3 + CuSO4 --> Cu(NO3)2 + H2SO4


What is the reaction CuSO4 5H2o plus heat?

CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O