Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:
2K + CuSO4 --> K2SO4 + Cu
Yes, white CuSO4 can absorb 1 to 5 molecules of H2O (mono- and penta-hydrates (blue) are formed).
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
CuSO4 is the chemical formula of copper(II) sulfate.
Dont know what is CuSO. But CuSO4 is copper sulphate..
These substances doesn't react.
When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.
Yes, white CuSO4 can absorb 1 to 5 molecules of H2O (mono- and penta-hydrates (blue) are formed).
The Cu2+ from CuSO4 is displaced by the Na+ from NaCl and CuCl2 and Na2SO4 are formed.
it is called SHALE :)
The insoluble product of the reaction between KOH and CuSO4 is copper(II) hydroxide (Cu(OH)2). This can be found by determining the products formed from the reaction between the potassium hydroxide (KOH) and copper sulfate (CuSO4), and then identifying the insoluble compound formed, which is copper(II) hydroxide.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
cu + H2so4 --->cuso4+2H two molecules of hydrogen evolves........
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Yes, CuSO4 is an electrolyte.
Nitric acid (HNO3) and copper(II) sulfate (CuSO4) will react in a double replacement reaction to produce copper(II) nitrate and sulfuric acid. The correctly balanced equation is: 2HNO3 + CuSO4 --> Cu(NO3)2 + H2SO4
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O