To find the volume of a 6.67 M NaCl solution that contains 3.12 moles of NaCl, use the formula:
[ \text{Volume (L)} = \frac{\text{moles of solute}}{\text{molarity}} ]
Substituting the values:
[ \text{Volume} = \frac{3.12 , \text{mol}}{6.67 , \text{M}} \approx 0.467 , \text{L} ]
Thus, the volume of the solution needed is approximately 0.467 liters, or 467 mL.
To find the volume of the solution containing 0.500 g of NaCl, first, calculate the moles of NaCl using its molar mass (58.44 g/mol). Then use the molarity formula (Molarity = moles/volume) to find the volume. The volume of a 0.150 M solution that contains 0.500 g of NaCl would be approximately 8.5 ml.
The volume is 57 mL.
The concentration of NaCl in a solution that contains 0.9 NaCl is 0.9 grams of NaCl per 100 grams of solution.
0,4 mol NaCl is 23,376 g.2,85 mol NaCl is 166,554 g to 1L.140 mL solution NaCl 2,85 M contain 0,4 mol NaCl.
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
To find the volume of the solution, first calculate the moles of NaCl in 0.500 g using its molar mass. Then, use the concentration to determine the volume using the formula: moles = molarity x volume. Rearrange the formula to solve for volume, which would be moles / molarity. Substituting the moles of NaCl and the concentration into the formula will give you the volume of the solution.
To calculate the molarity of the NaCl solution, first convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is 58.44 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters (750 mL = 0.75 L) to get the molarity. In this case, the molarity of the NaCl solution is 1.5 M.
To calculate the volume of NaCl solution containing 147 mg of NaCl, first convert the mass of NaCl from mg to grams (147 mg = 0.147 g). Then use the formula: [ \text{Volume (mL)} = \frac{\text{Mass (g)}}{\text{Concentration (M)}} ] Plugging in the values, [ \text{Volume (mL)} = \frac{0.147 g}{1.38 mol/L} \times 1000 mL/L ] You will get the volume in mL of the 1.38 M NaCl solution.
To prepare a 4.00 M NaCl solution, first calculate the moles of NaCl in 23.4 g. Then, determine the volume of water needed to make a total volume of 100.0 mL minus the volume of NaCl solution. Add the water to the NaCl to make a 100.0 mL solution.
To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.
Normal Saline Solution, or anything that contains 0.9% NaCl
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.