yes since kmno4 is an oxidizing agent so it will reduce to mn2+ and the nacl cl will be oxidised to cl2.
When alkenes react with KMnO4, they undergo oxidation to form diols or glycols.
NaCl and HCl doesn't react.
Alkenes react with potassium permanganate (KMnO4) through a process called oxidative cleavage, where the double bond is broken and oxygen atoms are added to the carbon atoms. This reaction results in the formation of diols (glycols) or ketones and carboxylic acids, depending on the conditions and the structure of the alkene.
aldehyde is less stable than benzene so it react readily toward kmno4
These compounds doesn't react.
When ethanol reacts with excess acidified KMnO4, it is oxidized to form ethanoic acid. The purple color of KMnO4 is decolorized to colorless Mn2+ ions during the reaction.
no
H2SO4 is typically used instead of HCl in the titration of KMnO4 because HCl can react with KMnO4 and form chlorine gas, which can interfere with the titration results. Additionally, H2SO4 provides the required acidic medium for the reaction to occur between KMnO4 and the analyte.
KMnO4 + NaNO2 -> KNO2 + NaMnO4
Kmno4 is more volatile and has lower boiling point unlike Nacl.
Benzene does not react directly with potassium permanganate (KMnO4) under normal conditions. Benzene is a stable aromatic compound and does not undergo typical alkene or alkane reactions with oxidizing agents like KMnO4.
In order to convert KMnO4 to K2MnO4, a reducing agent is typically needed. One common method involves using a reducing agent like a metal, such as zinc or iron, to react with KMnO4 in an acidic medium to produce K2MnO4.