No, the higher ranking pairs in each hand have priority and are compared first and a pair of Aces beats a pair of Kings.
The value of the lower pair is only relevant if the higher pairs in each hand are the same, for example KQ v K7. In this example the lower ranking pairs in each hand would be compared and because a Queen is higher than a seven, KQ beats K7.
In poker, a hand is ranked primarily by its highest combination. A pair of aces and a pair of sixes (two pair) beats a pair of kings and a pair of tens (also two pair) because aces are the highest-ranking cards. Therefore, the hand with aces and sixes wins.
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
The pair of queens beat the pair of tens, the nine and the ace are irrelevant. Queens are higher ranked than tens.
In poker, a pair of aces is the highest pair, so a pair of aces and a pair of sixes would beat a pair of jacks and a pair of queens. The ranking of the pairs determines the winner, with aces being the highest and jacks the lowest. Thus, the pair of aces and sixes wins.
In High Card Poker, the hand with the highest ranking combination wins. A hand of three Aces, a 2, and a 4 (three of a kind) beats a hand with a pair of Kings, a pair of Queens, and a 5 (two pair). Therefore, the three Aces hand wins.
In Texas Hold'em, the hand with the higher pair wins. In this case, a pair of aces is higher than a pair of kings, queens, or twos. Therefore, the hand with a pair of aces and a pair of twos would win over a hand with a pair of kings and a pair of queens.
Yes always. e.g. three sevens (777) beats a pair of kings and a pair of aces (KKAA)
The two pair, although lower, beat the pair of Aces.
The best hand to play against pocket aces in poker is typically a pair of aces or a pair of kings. These hands have the highest chance of beating pocket aces in a showdown.
No, a full house beats two pair
3 of a kind Aces can not beat a full house. In this particular case it is most likely that there was a pair and an ace already on the board, making the 3 aces and the pair on the board a higher full house then the other full house.
No. The pair of kings is only one pair. No matter how low your 2 pair is (for instance fours & fives) it can't be beat by one pair.