it is 600kg
no there is not
you have to go through it and in the end the rocket scientist battles you and if you win he gives you the gem back and then you can trade with sapphire and ruby
The house with the team rocket disguise is in the goldenrod tunnel, but you can't keep it forever. You have to return it. If you want to keep it, I'd recommend buying an action repay and putting disguise codes in it.
Beat all gym leaders and save the radio tower (from team rocket)
After you go to Team Rockets Underground Base in Mahogany town and help to drive out Team Rocket. Once your all finished up and have stopped the radio signal, Lance will give you the HM06 - Whirlpool. Then once you beat the Gym Leader in Mahogany Town (Pryce) you'll be able to use it.
F = ma (force equal mass times acceleration) Therefore a = F/m So acceleration changes in direct proportion to the change in force. Half the force gives half the acceleration.
Not enough information. One equation you can often use is Newton's Second Law: force = mass x acceleration Which, when solved for acceleration, gives you: acceleration = force / mass
Just use Newton's Second Law. That is, divide the force by the acceleration.
An object with a greater mass needs more force. Mass is what gives an object resistance to acceleration. Newton's Third Law: force = mass x acceleration, or acceleration = force / mass.
Earth's gravity.
The rocket's acceleration is created by the net force acting on it. There are three forces acting on the rocket: the thrust provided by the engines, gravity or weight, and air resistance. The acceleration is inversely proportional to the rocket's mass. This is Newton's Second Law: (acceleration) = (net force) / (mass) We need to think about the direction of the forces. The thrust acts upward (call this positive), and both gravity and air resistance acts downward (call these negative). So we get (acceleration) = (thrust - weight - air resistance) / mass A typical rocket engine will provide constant thrust as long as the fuel lasts. But as the engine consumes fuel, expelling the exhaust products out the back of the rocket, the rocket's mass decreases. This tends to increase the rocket's acceleration since acceleration is inversely proportional to the mass. In addition to the decreasing mass, the rocket's weight decreases as it moves farther from the center of the Earth--- this effect is described by Newton's Law of Gravity. The rocket's decreasing weight tends to increase its upward acceleration. The action of air resistance is more complicated, and ordinarily we ignore air resistance in simple models just to avoid the complication air resistance gives to the problem. In the standard air resistance model, air resistance scales with the square of the rocket's speed and the air density. The rocket is moving faster and faster, but the air density is also decreasing as it rises through the atmosphere. I think we can safely say the air resistance force decreases as the rocket gains altitude, but a detailed answer illustrating precisely how this force changes would require a numerical simulation. Hope this helps!
Force = (mass) x (acceleration) Acceleration = (force) / (mass) With the same force applied, a smaller mass has greater acceleration. A baseball has less mass than a shot has, so the same force gives it greater acceleration.
Acceleration is proportional to net force.That means that acceleration is equal to (net force) times (something).The 'something' is [ 1 / (the mass of the object being accelerated by the force) ].
A = f / m
Yes, the acceleration of gravity times the mass of the object gives a force that is the weight.
If a force of 30 N imparts an acceleration of 5 to an object and we desire only one fifth of that acceleration, then we apply only one fifth of that force. Take the 30 N and divide it by 5 and we find that 6 N is the force required to give our test object an acceleration of 1.
Constant velocity gives zero acceleration, force is mass times acceleration, thus if acceleration is zero then force is zero and equilibrium is zero force. Equilibrium = zero force :0=f=ma=mdv/dt = m0 when velocity is constant dV/dt=0.