Efficiency can be calculated using the formula: Efficiency (%) = (Actual Mechanical Advantage / Ideal Mechanical Advantage) × 100. In this case, the efficiency would be (3 / 4) × 100 = 75%. Therefore, the device has an efficiency of 75%.
Ma-Ma-Ma Belle was created in 1973.
Liwen Ma's birth name is Xiaoying Ma.
A 30 mA rating for an Earth Leakage Miniature Circuit Breaker (ELMCB) indicates the device's sensitivity to earth leakage currents, which is crucial for protecting against electrical shock and fire hazards. This means that the ELMCB will trip and disconnect the circuit if it detects a leakage current of 30 milliamperes (mA) or more. Such a rating is typically used in residential and commercial applications to enhance safety by minimizing the risk of electric shocks.
Jason Ma's birth name is Jason Pius Ma.
Ma Fuxing was born in 1854.
Yes, the 1000 mA has more that enough capacity to operate a 700 mA device. If the 700 ma adapter was original equipment with the device it was to charge, then the device is more than likely drawing about 500 to 600 mA. Look on the device's nameplate and you should see the mA draw.
yes, it will just charge the device faster..
Yes, 1 amp is equal to 1000ma and it will be able to operate a 850 ma device.
MA = Revolutions of input shaft / Revolutions of output shaft. (Input torque * MA) * efficiency = Output torque Note 100% efficiency = 1.0
Ideal mechanical advantage is the mechanical advantage when the efficiency of the pullefy system is 100%. It is a constant for that system of pulleys. Therfore it is not affected by increasing or decreasing the load.The MA of a pulley is equal to the number of supporting ropes.If the load is supported by one rope , the M.A of the system is 1. Efficiency is 1 for ideal pulley ( No loss of energy due to friction)If the load is supported by two ropes , the M.A of the system is 2. But Efficiency is still 1 for ideal pulley ( No loss of energy due to friction)If the load is supported by three ropes , the M.A of the system is 3. Efficiency is still 1 for ideal pulley ( No loss of energy due to friction) .And so on.Read more: How_does_increasing_the_load_affect_the_ideal_mechanical_advantages_and_efficiency_of_a_pulley_system
"Better" is an interesting word. I would guess that theoretical MA beats actual MA any day of the week. Some energy is lost in friction.
The ideal MA is 47.
Yes, you can use a 12-volt power source with a 0.5A capacity to power a 12-volt device that requires 400 mA. The power source provides sufficient current since 0.5A (500 mA) is greater than the device's requirement of 400 mA. Just ensure that the voltage remains stable at 12 volts, as that matches the device's specifications.
Yes, the maximum that the adapter can deliver is 1300 mA or 1.3 amps. The maximum that the device will draw is 200 mA or .2 of an amp.
The mechanical advantage (MA) is usually less than the ideal mechanical advantage (IMA) for a machine due to factors such as friction, inefficiencies in the machine's design, and energy losses through heat or sound. These factors cause the input work to be greater than the output work, resulting in a lower actual mechanical advantage compared to the ideal mechanical advantage.
A: Assuming 100% efficiency 320 ma
No, the capacity of the device is too large. The adapter will heat up and may even burn its internal windings open.