80 Friendship experience.
In Digimon World Dawn.... you need maximum friendship and level 40
lekismon digivolves to crescemon at level 33 if your friendship is at or above 80% and it has at least 2800 dark experence.
A:Talk to the other light fangs like pulsa and they will tell you about new digimon sightings acessglacier:Mega,Darkdramon lv.80 Taskcayon:Mega,Impereldramon fight mode lv.90 Trilleruins:Mega, Anubismon lv.70
Just mix two random digi-eggs, when it hatches it's an 80% chance it'll be a Numemon.
there are two ways to do this, one is get an exveemon and digivolve it to paildramon, the other is getting two ds's and one of them has to have a stingmon while the other has to have an exveemon, breed them together to get a pike egg, train it to its needed requirements and it will hatch into a paildramon which can turn into imperialdramon fighter mide or imperialdramon dragon mode, to digivolve into each you need 50000 dragon exp for DM and 50000 holy exp for FM and i think you need to be level 53.
Agumon digivolves to greymon in level 15 but you need 80+Fnd
Agumon digivolves to greymon in level 15 but you need 80+Fnd
In Digimon World Dawn.... you need maximum friendship and level 40
lekismon digivolves to crescemon at level 33 if your friendship is at or above 80% and it has at least 2800 dark experence.
A:Talk to the other light fangs like pulsa and they will tell you about new digimon sightings acessglacier:Mega,Darkdramon lv.80 Taskcayon:Mega,Impereldramon fight mode lv.90 Trilleruins:Mega, Anubismon lv.70
DNA digivolve exveemon and stingmon (lvl. 36 friendship 80% attack 230
Just mix two random digi-eggs, when it hatches it's an 80% chance it'll be a Numemon.
Assuming you mean the arithmetic mean, it is 80.
You mean what is 80 + 80 and it is 160....
80 = 80/1 as an improper faction
there is no world 80....
There are an infinite number of sets with mean 80. Here are some: {80, 80, 80}, {80, 80, 80, 80, 80, 80} {79, 80, 81}, {79, 79, 80, 81, 81}, {79, 79, 80, 82} (1, 80, 159}, {-40, 200} To produce a set of n numbers with mean 80, start with any set of n-1 numbers. Suppose their sum is S. Then add the number 80*n-S to the set. You will now have n numbers whose sum is S+80*n-S = 80*n So the mean of this set is 80.