looking for length of tube if i.d is 93mm and is to hold 1ltr of fluid
It is used at such places where we need to have high volume Or high CFM with low velocity and it can maintain its velocity till 5 meters of length
A liter equals 1dm³ in volume. Since 50dm³ are 50000cm³, a cuboid with the dimensions 50cm * 50cm* 20cm would fit as well as a tube of 1m height and 25.23cm diameter.
A longer tube causes the soundwave to have a longer wavelength, a lower frequency and hence have a lower pitch.
Orange shield
A tube contains enclosed air by a thread of mercury of 250mm long when tube is horizontal the length of air is 250 mm long. The pressure on the air column when atmospheric pressure is 750 mm Hg is 3 Pascal or 3 N / m2.
We would have to know the length of the tube.
The answer depends on the cross-sectional area as well as the length.
Volume of a cylinder (the test tube) = pi*radius2*height or length Volume = pi*15.52*204 = 49011*pi cubic mm
Measure the outer diameter of the tube and its' length. Calculate each tube volume and multiply by number of tubes. For those who want to calculate the inside liquid capacity of the shell side, it is advise to include the baffle volume with the tube bundle volume.
1.219197
7.6 ml
V=(L)(pi)(r)^2 L is length (ex: water occupies 9 m of a 10 m tube, i think meters is correct) r is radius of tube note: (pi)(r)^2 = area of a circle
The length of a tube is not related to its radius so you cannot.
It is used at such places where we need to have high volume Or high CFM with low velocity and it can maintain its velocity till 5 meters of length
A millilitre is a volume of 1 cm3. You can measure this quantity of volume by a measuring tube, burette or pipet tube.
SI units refer to normalised sets of units, not of equipment. For example. The SI unit for length is metre, volume is litre etc.
The answer depends on the shape of the 2 litres. If it is in the form of a long tube which is 2 cm is diametre, then you will not get a single nickel into it! 2902 nickels will occupy a volume of 2 litres.