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Can you answer show work A hockey puck is sliding along the ice with a constant velocity of 6 m s Its mass is 0 point 5 kg What force must be applied to bring the puck to a complete stop in 2 seconds?
Wiki User
∙ 12y ago
That's the basic calculation:
V0 - the starting velocity/speed (m/s)
a - acceleration (m/s)
t - duration of the acceleration (s)
v=v0+a*t
in this case if the puck wasn't moving and you have accelareted it for 2 seconds
v=0+6*2=12 (m/s)
If I missunderstood your question then let me apologize for it.......
Wiki User
∙ 16y ago
Wiki User
∙ 14y agoa = Δv/t = (6 m/s)/(2 s) = 3 m/s2
F = ma = (0.200 kg)(3 m/s2) = 0.6 N
The answer is correctly given to one significant digit.
Symbols:
Δ = "change in"
Units:
m = meters
s = seconds
N = newtons
Variables:
d = displacement (m)
t = time (s)
v = velocity (m/s) = Δd/t
a = acceleration (m/s2) = Δv/t
m = mass (kg)
F = Force (N) = ma
Wiki User
∙ 15y agoAccording to Newton or one of those old dead guys, the opposing force will be equal. So why doesn't the stick go flying 90-miles-an-hour in the opposite direction??? Only because it has a greater mass and there's a hockey player hanging on to it. 6 N
Wiki User
∙ 13y agoForce equals mass times acceleration.
Since the puck's velocity increased by 6 meters per second in 2 seconds its acceleration is 3 meters per second squared (6/2).
Its mass is 0.2 kg.
Therefore force = 0.2 * 3
Force = 0.6 newtons
Wiki User
∙ 12y agoDo your own homework, kid.
The steps to follow are:
- Find how much it must accelerate to reach a zero velocity (hint, acceleration can be negative)
- Multiply that by the mass of the puck to get a force.
I asked for help dummy. you weren't even any help. so go f off
It's like two calculations bro.
6 m/s
To accelerate to zero, you need to accelerate at -3m/s^2
The puck has a mass of 0.5 kg.
That's a total of -1.5N of force
Wiki User
∙ 13y ago3m/s squared
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