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Since the radius of Earth is far greater(rough: 6400km) than a few 100m, you can neglect that distance and still have g=9.80 (g=GM/(R^2), with R being the radius of earth, a few 100m dont do much difference in g's equation)

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14y ago
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13y ago

very simple. gravity is acting upon these objects the very same. no extra or no less gravity is being exerted upon the objects. the only reason they fall differently on earth is because of air resistance. the air pushes them backwards.

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14y ago

In fact, it is not exactly the same because in a vacuum, there is no air to create friction that decreases acceleration so the rate of acceleration tends to be greater than in a non-vaccum environment.

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13y ago

The free fall acceleration of the earth is approximately related to the distance from the surface by the following formula.

g = GM/(R2 + h)

where G = universal gravitational constant, M = Mass of Earth, R = Radius of Earth, h = distance from the surface of the earth

g = 3.98 * 1014 / ( (6.0 * 106 )2+ h)

as h increases to a very low value near the surface of the earth the value of g can be approximately taken to be constant near the surface of the earth.

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14y ago

Air resistance.

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12y ago

because u are entering the atmosphere

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Q: Explain why free fall acceleration near earths surface is constant?
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