In laboratory settings, you can make react a mixture of powdered sulphur
and iron filings by heating. The end product is Ferrous Sulfide;
Fe + S ----> FeS
Iron sulfides in nature are Pyrite and Marcasitewhose formula is; FeS2 .
Water molecules, H2O have hydrogen bonding between molecules which means it is a liquid until 100 oC, 212 oF. Carbon tetra chloride/ tetrachloro methane is heavy but boils at 76.8 oC
This reaction is:S + 6 HNO3 = H2SO4 + 2 H2O + 6 NO2
3 mole FeCl2 will react with 6 mole NaOH (stoechiometric mole ratio: 1 FeCl2 to 2 NaOH), so 3 mole FeCl2 (= 6 added -3 used) will be left over.
So far I come up with: HBr (aq) + MgSO3 (s) --> H2SO3 (aq) + MgBr2 (??)
-2.37 V (apex) Chace
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
An oxidation half-reaction involves the loss of electrons. In the options provided, the correct oxidation half-reaction is D. Fe + 2e- → Fe²⁺, as it shows iron (Fe) losing two electrons to form Fe²⁺. Options A and B represent reduction processes, while C does not depict an oxidation reaction.
Fe + S = FeS or 2Fe +3S = Fe2 +S3
The balanced chemical equation for this reaction is: FeS + 2H⁺ → Fe²⁺ + H₂S
The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1. For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.
Fe2+Cl=FeCl (Original)Fe2+2Cl=2FeCl (Balanced)---- The two in front of the FeCl balances Fe by making it Fe2, but also turns Cl into Cl2. So you put a 2 in front of the Cl reactant, balancing Cl and Fe.
Cu2+(aq) + 2e- → Cu(s) and Fe(s) → Fe2+(aq) + 2e-
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
Fe + S = FeS
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
Fe(s) + Sn2+(aq) -> Fe2+(aq) + Sn(s)
The chemical formula for iron(II) sulphate is FeSO4, for iron(III) sulfate is Fe2(SO4)3 The formula for iron(II) sulfide is FeS, iron(III) sulfide Fe2S3