dBm us almost exactly the same as dB.
The only difference is that there is a reference of 1 Watt = 0 dB, and 1 mW = 0 dBm.
dBm is defined as power ratio in decibel (dB) referenced to one milliwatt (mW). It is an
abbreviation for dB with respect to 1 mW and the "m" in dBm stands for milliwatt.
dBm is different from dB. dBm represents absolute power, whereas in audio engineering the decibel is usually a voltage ratio of two values and is used then to represent gain or attenuation of an audio amplifier, or an audio damping pad.
PdBm = 10*log10(1000*10W) = 40dBm
Mic level is -56 to -40 dbm. Line level is either -10 dbm or 4 dbm. You need a preamp to amplify a microphone to line level.
dBm is power with reference to 1 milliwatt, expressed on the logarithmic scale (decimals). To compute dBm x, from power P, the following formula is used:x = 10log10(P)This is ten times the logarithm to the base 10 of P.
Divide by 1000 to convert grams to kilograms. Then multiply by 2.2046 to convert kg to pounds.
You cannot convert between the two since they measure different attributes.
Multiply psi x 0.07 to get atmospheres.
20 dbm
the first convert the power in dBm to MW, the define of dBm=10 log (P MW) -10 log ( 1mw). example: let P=-2 dBm convert this to dB? answer: Pmw= inv log(-2/10)=0.630mw*1000 micw/mw=630 microw 10log(630)=28dB
Well, the question your asking is basically impossible. It's like asking to convert a gallon of water into cans of pop. It is possible to convert the gallon of water into cans of water not soda. So you can convert dBm to watts, not dBi.
Well, the question your asking is basically impossible. It's like asking to convert a gallon of water into cans of pop. It is possible to convert the gallon of water into cans of water not soda. So you can convert dBm to watts, not dBi.
PdBm = 10*log10(1000*W)
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
dBm is defined as power ratio in decibel (dB) referenced to one milliwatt (mW). It is an abbreviation for dB with respect to 1 mW and the "m" in dBm stands for milliwatt. dBm is different from dB. dBm represents absolute power, whereas in audio engineering the decibel is usually a voltage ratio of two values and is used then to represent gain or attenuation of an audio amplifier, or an audio damping pad.
dBm is defined as power ratio in decibel (dB) referenced to one milliwatt (mW). It is an abbreviation for dB with respect to 1 mW and the "m" in dBm stands for milliwatt. dBm is different from dB. dBm represents absolute power, whereas in audio engineering the decibel is usually a voltage ratio of two values and is used then to represent gain or attenuation of an audio amplifier, or an audio damping pad.
Put the power in milliwatts in cell A2, and then use the following formula to get the power in dBm. =10 * LOG(A2)
Here's how to convert dB units (with usually a 1 Watt or whatever 1 value as reference) to dBm units (with a 1 miliWatt reference value):x= value to be convertedx [dB]= x + 30 [dBm]Proof:P= 1 Watt--> 10*log10(1)= 0 [dB] (this is 1 Watt in dB)--> 10*log10(1/(1*10^(-3)))= 10*log(1*10^3)= 30 dBm (this is 1 Watt to dBm)Now, if you do whatever number of examples you want to do, you'll end up in concluding the conversion dB to dBm is totally linear without of actually having to proof the linear properties. (i'm too lazy to write it here).Hope this helps....Regards,STMI
Two ways to do it. In this particular problem, it's a matter of opinionwhich one is easier and which one is harder.Way #1:Convert dBm to watts, multiply by gains, convert output watts to dBm.+20 dBm = 0.1 watt.Output power = (0.1 watt) x (ap1) x (ap2) x (ap3) = 0.1 x 10 x 4 x 23 = 92 watts = +49.64 dBmWay #2:Convert each gain ratio to dB, then add all dB to input power.ap1 = 10 = 10 dBap2 = 4 = 6.02 dBap3 = 23 = 13.62 dB+20 dBm + 10dB + 6.02 dB + 13.62 dB = +49.64 dBm
Yes, DBM (data base management) is real.