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How do you prepare 1millimolar silver nitrate solution from 0.5 molar silver nitrate?
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
How do you prepare 100 mM phosphoric acid?
To prepare 100 mM phosphoric acid solution, you can dilute a more concentrated phosphoric acid stock solution to the desired concentration by adding the appropriate volume of water. Calculate the volume of the stock solution needed using the dilution formula: C1V1 = C2V2, where C1 is the concentration of stock solution, V1 is the volume of stock solution needed, C2 is the desired concentration (100 mM), and V2 is the final volume of the solution.
How do you make 62.5 mM Tris-HCl?
To make 62.5 mM Tris-HCl solution, you would need to mix the appropriate amount of Tris base and HCl to achieve a final concentration of 62.5 mM. The calculation involves considering the molecular weights of Tris and HCl to determine the amount needed to make the desired concentration.
How do you prepare 10 mM ammonia?
- Transfer 0,057 mL of 30 % ammonia solution, with the aid of a micropipette in a volumetric flask (volume 100 mL) - Add distilled (or demineralized) water up to the mark, at 20 0C - Put the stopper and stir.
1 mL of 10 mM NaCl solution was mixed with 4 mL of 0.05 M CaCl2 solution The final concentration of Cl- is?
The initial moles of NaCl in 1 mL of 10 mM solution is 10 µmol. The initial moles of Cl- in 4 mL of 0.05 M CaCl2 solution is 0.2 µmol. Therefore, the total moles of Cl- after mixing is 10.2 µmol. The final concentration of Cl- is 2.55 mM.
How do you make 50mM ammonium acetate solution?
One mole of ammonium acetate is equal to 77.08g (this is the formula weight, FW, of ammonium acetate, which can be found on the side of the bottle). Another way of representing this is 77.08/mol (so, in one mole of ammonium acetate, there are 77.08grams of ammonium acetate).We have to use the FW value to calculate molarity (moles of solute per L of solvent).I am not sure what volume of the 50mM solution is desired, so I will assume that you need 1 L.50mM is equal to 50milli-moles of solute/1 L of solvent, which is the same as 0.05moles/L. This is what the math looks like:77.08g/mol ammonium acetate x 0.05mol/L = 3.854g/LSo, to make a 50mM solution of ammonium acetate in 1L of water, you will need to dissolve 3.854g of ammonium acetate into 1L of water.
How do you make this solution?
I don't know how to make the solution below. Low salt buffer: 10 mM phosphate buffer, 10 mM NaCl, pH 7.4. Could you tell me the method in detail?
How do you prepare 100mM ammonium acetate?
To prepare the buffer using solid form reagents, prepare a 0.1 M ammonium acetate solution by dissolving 7.7 g ammonium acetate in a 1000 ml water. Adjust 1 L of this solution to pH 4.5 by adding acetic acid (about 8 ml) and 5 ml of 1 M p-TSA (equivalent to 5 mM p-TSA).
How many micromoles of Ammonia present in 25ml of 6mM Ammonium Sulphate?
Assuming that "mM" means "millimolar", the solution specified contains 6 millimoles of ammonium sulphate per liter. Therefore, 25 ml of the solution contains 6(25/1000) = 0.15 millimoles. By definition, there are 1000 micromoles per millimole. Therefore, 0.15 millimoles = 150 micromoles.
What is the solution for o.015km to mm?
show solution convert 0.015 km to mm
How do you make 3 litres of 5mM Ammonium acetate?
To make 3 litres of 5mM Ammonium acetate solution, you would need to calculate the amount of Ammonium acetate needed based on its molecular weight. Once you have determined the mass needed, dissolve it in sufficient water to make the final volume of 3 litres. Keep in mind to use a balance to measure out accurate amounts of the compound for precise results.
How to dilute 100 mM to 5 mM?
To dilute a 100 mM solution to 5 mM, you would need to dilute it by a factor of 20. To do this, you can add 19 parts of a suitable solvent (such as water) to 1 part of the 100 mM solution. Mix thoroughly to ensure a homogeneous 5 mM solution.
How many mM OF Na are in 150 mM NaCl solution?
Also 150 mM of sodium.
How do you prepare 20 mM of trolox?
To prepare a 20 mM solution of Trolox, first determine the molecular weight of Trolox, which is approximately 250.3 g/mol. Calculate the amount needed by multiplying the desired molarity (20 mM or 0.02 M) by the volume of the solution you wish to prepare (in liters) and the molecular weight. For example, to make 1 liter of a 20 mM solution, dissolve 5.01 grams of Trolox in a suitable solvent, typically distilled water, and then adjust the final volume to 1 liter with the same solvent.
What does mM stand for in biology?
mm means millimeter there are 10 millimeters in a centimeter
Which solution contains the correct number of significant digits for the product 2.80 mm 0.1 mm?
FMOT @ Shee_Coldd
How do you prepare 1millimolar silver nitrate solution from 0.5 molar silver nitrate?
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
