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Salt influences heating/cooling of water.

When we want to heat a seawater from 20 to 50 degrees in an electrical kettle, we'll spend more time and electricity for doing it, than for usual water.

Proof

To determine the value of heat, that has been added/removed to/from water the following law is used:

dQ=m*C*dT

where

dQ - amount of added/removed energy (heat), kJ

m - mass, kg

C - specific heat capacity, kJ/kg-K (depends on a type of material)

dT - change of temperature, C (or K)

Changing specific heat capacity, one changes ability of a material (in the case - water) to absorb/dissipate heat, in a same range of a temperature change.

Example. There is 1 kg of usual water, its' temperature is changed on 10 deg K.

C of water is 4.18 kJ/kg-k. Amount of heat Q, that water excepts is:

Q=1*4.18*10=41.8, kJ

C of salted water is 4.8 (depends on salinity), so amount of heat, that salted water absorbs is 48 kJ.

That means, that to change temperature of salted and usual water on a same amount of degrees, we need to put more heat in a salted water.

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Does tap water or salt water cause metals to rust faster and why?

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Does the temperature of water affect how rapidly salt will dissolve?

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Related Questions

What are the factors that may affect the rate at which the salt dissolves in water?

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Cold water simply slows down the rate at which salt dissolves.


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How does stirring affect dissolution of common salt in water?

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