KWh is an amount of energy, w(watts) is a rate of energy (power). You can't equate them.
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1.88hp
1......AND THAT WAS ME!!!!DESIREE' W. I ROCK HAPPY HALLOWEEN!
If you assume all of the 1080 W of electrical power is converted to heat flow then you can use the conversion 1 W = 2.39 x 10^-4 KCal/sec to get 1080 W = .258 KCal/sec. There is probably less then that as some of the wattage has to run the fan motor, but it gives you an upper limit on how much heat flow to exoect.
1000 words that a picture is worth
There are zero amps in 32 kWh. Watts are the product of amps times volts. Without stating what the voltage is, this calculation can not be made. I = W/E is the formula to find amperage but there has to be a time constant if kWh is used. Usually the question is asked as to how many amps are in 32 kW.
1 joule = 1 ws (watt-second); since 1 kw = 1000 w, and 1 h = 3600 seconds, it follows that 1 kwh = 3,600,000 ws or joule.
I kW = 1000 W 100 / 1000 = 0.1 So a 100 W bulb uses 0.1 kW For one hour that's 0.1 kWh
6000W x 1 hour = 6 KWH
1. The kilowatt hour (kWh) is a unit of energy. 2. The unit of power is simple the kilowatt (kW). 3. 1 kW = 1 000 W; 33 W = 0,033 kW.
A 100 W light uses a power of 0.1 kW all the time it's switched on, which means it uses 0.1 kWh each hour. So it uses 1 kWh in ten hours. In a month of 30 days totalling 720 hours, it would use 72 kWh of energy.
I assume you mean 0.09 dollars per kwh? 6 * 100w = 600w (joules per second) 600w / 1000 = 0.6kw 0.6kw * 6h = 3.6 kwh 3.6 kwh * 0.09 = 0.324 dollars So your awnser is 32 cents
A Joule is a Watt-second (or W=J/s). Therefore, 3.5 kWh = 3.5*3600 kWs = 3.5*3600*1000 W-s = 12.6 million Joules
A kilowatt hour (kWh) is used to measure energy consumption. It is defined as 'the energy consumed, over a period of one hour, at a rate of one kilowatt'.To determine how many kilowatt hours are consumed, you must multiply the power of the lamp, expressed in kilowatts, by the length of time it is in use, expressed in hours.So, a 45-W lamp will use: (45/1000) x 1 = 0.045 kWh per hour of use.
In one day, 60x24 watt hours or 1.44 kWh. In 60 days, 86.4 kWh.
kWh= power(watts 'W') multiplied by time(hours 'h') takenThe formula is;- kWh= W X heg; an electrical coocker with a plate of 3.6 kW was used to coock food for 5 hours. calculate energy consumed in kWh.kWh= W X h ;- given W= 3.6kW; h=5hrskWh= 3.6 X 5= 18kWhThe Energy consumed was 18kWh
1 kW = 1000 W 200 / 1000 = 0.2 So the 200 W bulb is also a 0.2 kW bulb. 0.2 x 30 = 6 So a 200 W bulb uses 6 kWh in 30 hours. Now all you have to do is find the price of a kWh, and take that times 6.