Each phase supplies 15 kVA. The primary has a line-to-neutral voltage of 277 v so the line current is 15,000 / 277 or 54 amps. The secondary has a line-to-neutral voltage of 120v so the current is 15,000/120 or 125 amps.
Around .0007 Watts. Watts=Amps x Volts 0.0007W=0.001A(1mA) x 0.7V
Amps is a measurement of current. Watts (or kilowatts) is a measure of power. To get the power from the current, you have to know the electrical potential or volts used to produce the current. Amps × Volts = Watts (or Current × Electrical Potential = Power). Incidentally, a kilowatt is 1000 watts, so you'll have to divide your answer by 1000. e.g. if your volts is 40, then 25 amps × 40 volts = 1000 watts. 1000 watts (divided by 1000) is 1kw or kilowatt.
The answer is 40,000 divided by 415 or 96.38 Amps. Watts is volts times amps.
Any value - you must supply the resistance.
The amperage drawn from batteries is governed by the connected load. The voltage of the batteries can be one of two voltages. in parallel the 8 batteries will give you a voltage of 6 volts. In series the 8 batteries will give you a voltage of 48 volts. The amp/hour capacity of the batteries will give you the amount of current the device can draw over a specific length of time. Equation to fine amperage is I = W/E, Amps = Watts/Volts. Watts = Amps x Volts.
2.083 amps
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
To calculate the amperage in the secondary side of a transformer, you can use the formula: Amps = kVA / (Volts x Sqrt(3)). For a 250 kVA transformer with a 220-volt secondary, the amperage will be approximately 660.4 Amps.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
This will still only produce 12 volts. It will produce 1200 watts. watts is the result of Volts times Amps.
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
36.6 amps maximum at 120 volts, but should not be loaded to over 29 amps. At 240 volts it will produce a maximum of 18.3 amps but never loaded to any more than 14.6 amps.
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
The unit of power is expressed in watts, and the product of current (Amps) and voltage (volts) is power there fore if you multiply the amps and the volts give watts. so 20 x 240 will give you a 4800 watts of power.
500,000 watts/240 volts = 2,083.34 Amps (single phase)
If your generator is rated at 1000 watts continuous......and you are using 120V.....available amps are 1000/120 =8.3 .