3 Hydrogen atoms, 2 Oxygen atoms.
BeC2O4 = 97.0 g/1 mol BeC2O4-3H2O = 151.0 g/1 mol 3.21 g BeC2O4-3H2O * 1 mol/151.0 g = 0.021258 mol BeC2O4-3H2O 0.021258 mol BeC2O4-3H2O * 97.0 g/1 mol = 2.06 g BeC2O4
Atoms of the elements are the simplest particles of compounds. The definition of an element is a substance that cannot be broken down into a simpler substance or interconverted.
it would be combustion 3NaHCO3 + C6H8O7 ---> C6H5Na3O7 + 3CO2 + 3H2O When a chemical reaction has CO2 and H2O in it, its then stated as a combustion.
Many chemical compounds from living things can benefit human health. In different cultures natural compounds were used for thousands of years. Sometimes they're used as drugs. The classic example might be penicillin, a compound made by a fungus and used as the first widely-available antibiotic. Many edications come from plants.
Organic compounds are compounds necessary to life, and most macromolecules necessary to life contain carbon.
3H2O has 6 hydrogen atoms and 3 oxygen atoms.
9
2NaAlO 2+3h2O
It's 3 molecules of water. A water molecule has 3 atoms. So there are 9 atoms in 3H2O
There are 6 molecules in the formula 3H2O: 3 molecules of water (H2O) each composed of 3 atoms (2 hydrogen and 1 oxygen).
3H2O + SO4 is not a defined chemical formula. 3H2O represents 3 water molecules and SO4 represents sulfate. The reaction or compound formed would depend on the specific conditions under which these substances are combined.
BeC2O4 = 97.0 g/1 mol BeC2O4-3H2O = 151.0 g/1 mol 3.21 g BeC2O4-3H2O * 1 mol/151.0 g = 0.021258 mol BeC2O4-3H2O 0.021258 mol BeC2O4-3H2O * 97.0 g/1 mol = 2.06 g BeC2O4
To demonstrate the conservation of mass in the chemical reaction 3NaOH + H3PO4 -> Na3PO4 + 3H2O, you would need to show that the total mass of the reactants (3NaOH + H3PO4) is equal to the total mass of the products (Na3PO4 + 3H2O). This can be done by calculating the total mass of each side of the equation using the molar masses of the compounds and ensuring they are equal. This illustrates that mass is conserved in the reaction.
Al2O3 + 3HBr -> Al2Br3 + 3H2O Aluminium tribromide is readily hydrolysed so the hypothetical end product will react further to give a mix of AlBr(OH) compounds. The best preparation is Al metal plus bromine.
It is: C2H5OH+3O2 ----> 2CO2+3H2O
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
It's 3 molecules of water. A water molecule has 3 atoms. So there are 9 atoms in 3H2O