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Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023

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How many atoms are in a sample of 1.83 moles of potassium (K) atoms?

Okay, a mole of potassium perchlorate contains 6.02x1023 formula units of potassium perchlorate, but you're asking about individual atoms. So, let's look at the formula: KClO3. That's 1 potassium, 1 chlorine, and 3 oxygens, for a total of 5 atoms per formula unit. Now, multiple 5 by Avogadro's number above, to get 30.1x1023, which simplifies to 3.01x1024 atoms.


Does a sample of glucose C6H12O6 contain 1.261e21 atoms of carbon?

Are you familiar with mole concept. Well according to it 1 mole of anysubstance contains 6.023e23. First calculate the molecular mass of glucose which is (6*12)+12+(6*16)=180=y gm(say). Now find the mass of the sample glucose say x gm. Calculate the number of moles of glucose present which is found out by x/y. If its exactly 1 mole then the number of carbon atoms present are 6.023e23. Else use unitary method to find out for other values. For your mentioned number of carbon atoms the 0.0021 moles of glucose present.


How many sulfur atoms are in a molecule of sulfuric acid (H2SO4)?

We know from looking at the molecular formula that one mole of molecules of H2SO4 contains 2 moles of atoms of hydrogen, 1 mole of atoms of sulfur and 4 moles of atoms of oxygen.


How many moles are in 3.52E20 molecules of water?

1 mole of substance contains 6.02 x 1023 of its constituent particles. Accordingly, there would be 5.85 moles (of the substance) in a sample containing 3.52 x 1024 particles.


How many moles is 0.75g of Na2CO3?

The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.

Related Questions

Which sample contains the greatest number of atoms a sample of Mn that contains 3.29E plus 24 atoms or a 5.18 mole sample of you?

Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.


What is the mass of 4 moles of fluorine atoms?

The mass of 4 moles of fluorine F atoms is 151,98 g (because fluorine is a diatomic element).


Which sample contains the greatest number of atoms a sample of Al that contains 8.18E plus 23 atoms or a 5.16 mole sample of S?

Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.


How many moles of fluorine molecules react with one mole of magnesium atoms?

One: The formula for magnesium fluoride is MgF2. Since each mole of fluorine molecules, which have the formula F2, contains two moles of fluorine atoms, one mole of each is the right ratio.


How many moles of fluorine in 3 moles of borontrifluoride?

Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.


How many moles are in 1.50 x 10 to the 23 atoms of fluorine?

1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.


How many moles of N2O molecules are present in a sample that contains 5.23 moles of nitrogen atoms?

Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.


How many moles of fluorine are in 3.2 moles of xenon hexafluoride?

There are 19.2 moles of fluorine in 3.2 moles of xenon hexafluoride. Xenon hexafluoride has 6 fluorine atoms in each molecule, so you multiply the moles of xenon hexafluoride by 6 to find the moles of fluorine.


How many moles are in 45g of F?

The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.


If a sample of pure silver (Ag) contains 3.35 x 1022 atoms of silver how many moles of silver are in the sample?

To find the number of moles of silver, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. The number of moles can be calculated using the formula: [ \text{moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}} = \frac{3.35 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0556 \text{ moles}. ] Thus, the sample contains approximately 0.0556 moles of silver.


How many moles in 1.5 x 1023 atoms of fluorine?

0,25 moles F2


How many moles of carbon atoms can be obtained from the decomposition of C6H6 in a 1.68 moles sample?

Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.