Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?
The sample of______ contains the greatest number of atoms.
Answer:
In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.
The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / mol
To convert 5.16 moles of S to atoms of S:
atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol S
Multiply by atoms per mole. Moles cancel out.
The sample of Al contains 8.18E+23 atoms.
Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
Dichromate has 7 oxygen atoms (Cr2O7-2)
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
All atoms have atomic numbers which are the same and the atoms have the same number of electrons.
1
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Dichromate has 7 oxygen atoms (Cr2O7-2)
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
Number of moles = mass / molar mass, so the answer is the one with the greatest molar mass. This is plutonium.
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
one mole of all substances contains 6.022 x 10^23 atoms =number of atoms in 22400 cm^3 of any gas at STP
This depends on the mass of the gold sample.
The number of atoms is 1,50553521.10e23.
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
150 (50 x 3)