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How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 1024 fluorine atoms?
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
How many atoms are in a sample of 1.83 moles of potassium (K) atoms?
Okay, a mole of potassium perchlorate contains 6.02x1023 formula units of potassium perchlorate, but you're asking about individual atoms. So, let's look at the formula: KClO3. That's 1 potassium, 1 chlorine, and 3 oxygens, for a total of 5 atoms per formula unit. Now, multiple 5 by Avogadro's number above, to get 30.1x1023, which simplifies to 3.01x1024 atoms.
How many moles are in one molecule?
MolesOne mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes. You get the picture? One mole of molecules is 6.02 × 1023 molecules.
What is the number of Cl- ions in 21.04 gram sample of AlCl3?
1 mol of AlCl3 has mass 133.5 g and has 3 mol Cl- atoms so 400.5 g AlCl3 means 3 mol AlCl3 which means 9 mol Cl- atoms. So Ans = 9 X 6.022 X 1023 = 5.4198 X 1024 Cl- atoms
What is the mass of 3.01 x 1024 molecules of CL2?
In one mole of any element, there are 6.022*1023 atoms, Avogadro's number.3 mol Cl * (6.022*1023 atoms Cl/mol Cl) = 1.8066*1024 atoms ClTherefore, there are approximately 1.807*1024 atoms in three moles of chlorine.Be careful with this answer because the question probably carries hidden in it the expectation that you know that chlorine gas is diatomic. If that is the case, what is really being asked is how many atoms are in 3 moles of chlorine gas. When you answer that question be certain that you clarify your understanding. 3 moles of chlorine gas (Cl2) has 6 moles of chlorine atoms. 6 x NA will give you the answer.
How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 1024 fluorine atoms?
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
Which sample contains the greatest number of atoms a sample of Mn that contains 3.29E plus 24 atoms or a 5.18 mole sample of you?
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Which sample contains the greatest number of atoms a sample of Al that contains 8.18E plus 23 atoms or a 5.16 mole sample of S?
Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
How many moles of N2O molecules are present in a sample that contains 5.23 moles of nitrogen atoms?
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
What it the total number of atoms in one molicule in carbon dioxide?
1 mole C = 12.011g C 1.2g C x 1mol C/12.011g C = 0.10 mole C rounded to two significant figures
What is the mass of a sample of sodium that contains 2980 atoms?
Not much! 2980 atoms sodium [1 mole Na/6.022 X 1023 (atoms)][22.99 grams/1 mole Na] = 1.138 X 10 -19 grams sodium ====================
How many grams are in 2.92 x 1023 atoms of tin?
There are 57.6 grams of tin in that sample.
How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?
1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K
How many atoms are in a 341 g sample of scandium?
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
How many moles of Cr are there in a sample of Cr that contains 4.37E 23 atoms?
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
How many moles are present in a sample of 3.2x10 atoms of nickel?
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
How many moles of P are there in a sample of P that contains 3.78E plus 24 atoms?
The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert atoms to moles:moles P= 3.78E+24 atoms P1 mol P = 6.28 mol P6.02 x 1023 atoms PMultiply by moles per atom. Atoms cancel out.
