1 mol of AlCl3 has mass 133.5 g and has 3 mol Cl- atoms
so 400.5 g AlCl3 means 3 mol AlCl3 which means 9 mol Cl- atoms.
So Ans = 9 X 6.022 X 1023 = 5.4198 X 1024 Cl- atoms
A Gram of OG Kush is around 20-25 Depending on the condition and how Dank. I would recommend you look at it, smell it, and sample it before you buy in big amounts.
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
you would have 5 g of Wagonium-292
Gram Negative
gram
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The gram atomic mass of aluminium is 26.9815, and the gram atomic mass of chlorine is 35.453. The formula shows that there are three chlorine atoms for each aluminium atom in the compound. Therefore, the mass fraction of aluminium in the compound is 26.9815/[26.9815 + 3*(35.453)] or about 0.20235004, and the grams of aluminium present are 20.24, to the justified number of significant digits. _______________________________________ *An exact integer.
85.2 gram LiF sample is equivalent to 3,28 moles.
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
No, even a small 1 gram sample of iron contains a very large number of iron atoms. Iron has a molar mass of 55.85 g/mol, so 1 gram of iron would contain about ( \frac{1}{55.85} ) moles of iron atoms, which is approximately ( 6 \times 10^{22} ) atoms.
To calculate the total number of moles in the 52.0 gram sample of NaN3, divide the given mass by the molar mass of NaN3. First, determine the molar mass of NaN3 by summing the atomic masses of its elements (sodium, nitrogen, and three times the atomic mass of nitrogen). Then, divide the mass of the sample by the molar mass of NaN3 to find the number of moles.
To calculate the number of molecules, you first need to determine the number of moles of H2 in the 21.25 gram sample using the molar mass of H2 (2 grams/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
The density of water at standard temperature and pressure is 1 gram/milliliter. The size of the sample is irrelevant. If the sample is pure, then one drop of it has the same density as a tankerful of it has.
12
700 million years