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How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Which sample contains the same number of atoms as a gram atomic mass of he?
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
What is the number of atoms in 1 gram of iodine?
The answer is 4,745.10e21 atoms.
How many atoms are in a 341 g sample of scandium?
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Which sample contains the same number of atoms as a gram atomic mass of he?
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
How many atoms are in a 12.0 grams sample of sodium?
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
What is the number of atoms present in a 20 gram sample of Lithium?
To calculate the number of atoms in a sample of lithium, you first find the moles using the molar mass. Lithium's molar mass is approximately 6.94 g/mol. Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
What is the number of atoms in 1 gram of iodine?
The answer is 4,745.10e21 atoms.
How many atoms are in a 341 g sample of scandium?
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
How many moles of fluorine atoms are in a sample of fluorine that contains 7.45 x 1024 fluorine atoms?
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
How many atoms are in 1 gram of sulfur?
There are approximately 6.022 x 10^22 atoms in 1 gram of sulfur based on Avogadro's number, which is the number of atoms or molecules in one mole of a substance.
What is the number of Cl- ions in 21.04 gram sample of AlCl3?
1 mol of AlCl3 has mass 133.5 g and has 3 mol Cl- atoms so 400.5 g AlCl3 means 3 mol AlCl3 which means 9 mol Cl- atoms. So Ans = 9 X 6.022 X 1023 = 5.4198 X 1024 Cl- atoms
A sample of Se weighs 20.5 grams will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams?
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many atoms of lithium are in 18.7 g?
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
