How much heat engery is required to raise the temperature of 5 kilograms of coal from 20 c to220 c?

Answer 1

The amount of heat energy (q) gained or lost by a substance is equal to the mass of the substance (m) multiplied by its specific heat capacity (Cg) multiplied by the change in temperature (final temperature - initial temperature) q = m x Cg x (Tf - Ti)

q is what we are finding.

m of coal = 5 kg

Cg of coal (anthracite) = 1.38 kJ/kg-K (kilojoules per kilogram-Kelvin)

Tf = 220 °C.

Ti = 20 °C.

using the data above.

q = m x Cg x (Tf - Ti)

q = 5 x 1.38 x (220 - 20) -- temperature change same in K or °C

q = 5 x 1.38 x 200

q = 1380 kilo-joules(kj) or 1.3 x 106 joules

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The formula is

Q=m*c*(T2-T1)

Energy=mass*specific heat capacity*( temperature higher - temperature lower)

(assuming the volume of your substance doesn't change during the heating)

Energy Required = Mass x "Specific Heat Capacity" x Temperature change

For anthracite coal, the specific heat is 1.38 kJ / kgK , yielding E = 1.38 (5kg)(200K) = 1380 kJ.

Answer 2

Just took the exam, the answer is 1314718j. The previous answer on here was wrong so gt it wrong on my test and pennfoster gave me the correct answer, which is this.

Repeat, the answer is 1,314,718 j

Answer 3

You need the specific heat of coal.

starting temperature: 20c+273=293K

final temperature: 200c + 273= 473K

Heat (KJ) = Mass(Kg) x Specific Heat(KJ/Kg-K) x Change in Temperature(K)

Heat= (5 Kg) x (1.26 KJ/Kg K) x (473K-293K)

Required Heat energy= 1,134 KJ

Answer 4

The heat energy required to raise the temperature of 5 kilograms of coal from 20 C to 220 C is 1,300 kJ.