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How much heat in kcal must be added to 5.0 kg of water at room temperature 20C to raise its temperature 44C?
Wiki User
∙ 12y ago
If you mean the final temperature is 44C, then do the following:
Q = mcΔT
m = 5.0kg H2O = 5000g H2O
cH2O = 1.00cal/g*C
ΔT = 44C-20C = 24C
1000cal = 1kcal
1000g = 1kg
50kg H2O = 1000g H2O/1kg H2O = 5000g H2O
Q = 5000g H2O x 1.00cal/g*C x 24C = 120,000calories
120,000cal x 1kcal/1000cal = 120kcal
If you mean the temperature change is 44C, then do the following:
Q = mcΔT
m = 5.0kg H2O = 5000g H2O
cH2O = 1.00cal/g*C
ΔT = 44C
1000cal = 1kcal
1000g = 1kg
50kg H2O = 1000g H2O/1kg H2O = 5000g H2O
Q = 5000g H2O x 1.00cal/g*C x 44C = 220,000 calories
220,000cal x 1kcal/1000cal = 220kcal
Wiki User
∙ 12y ago
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