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How much heat is required to convert 1 kg of ice to liquid?
lf = 3.35 x 105 J kg-1 This much amount of heat required to convert 1 kg of ice to liquid Mani.Ra
What is one third of a kilo?
1/3 of a kg: - 0.33 KG - 0.73 pounds - 11.75 ounces Google Calcualtor can be used for conversions, eg: - If you type in "1 mile in kilometres" into Google, it will give you the correct answer. (1 mile = 1.609344 kilometers)
How much is ST lb - kg in lbs?
53,5 kg
How much is 152 kg in cg?
152 kg = 15,200,000 cg (1 kg = 100,000 cg)
Motor rated to 10000kn How many kg can it lift?
1000 Kn wou much Kg
How much milk is required to make 1 kd khoya?
10litres = aproximatly 10.35kg milk makes 1 kg cheese
How much heat is required to convert 1 kg of ice to liquid?
lf = 3.35 x 105 J kg-1 This much amount of heat required to convert 1 kg of ice to liquid Mani.Ra
How much steel required for 100 square meter room?
1000 kg
How much aluminum is required to melt 2 kg of aluminum?
800 kj
How much energy is required to vaporized 1.5 kg of copper?
7095 kJ
How much milk required for 1 kg curd?
Approximately 1 liter of milk is required to make 1 kg of curd. This is because curd is typically made by fermenting milk with the help of bacteria culture, which results in curdling and thickening of the milk.
How much energy is required to vaporize 2 kg if aluminum?
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
How much energy is required to vaporize 1.5 kg of copper?
1650kj
How much force is required (in Newtons) to accelerate a 10-kg bicycle, along with its 60-kg rider, at 2.5 m/s2?
175
How much energy is required to melt 1.5 kg of gold?
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
How much energy is required to vaporize 1.5 kg of aluminum (refer to table of latent heat values.)?
To calculate the energy required to vaporize 1.5 kg of aluminum, we need to use the latent heat of vaporization for aluminum, which is approximately 10,900 J/kg. The energy required can be calculated using the formula: Energy = mass × latent heat of vaporization. Thus, for 1.5 kg of aluminum: Energy = 1.5 kg × 10,900 J/kg = 16,350 J. Therefore, 16,350 joules of energy is required to vaporize 1.5 kg of aluminum.
How much grip strength is required to turn a door knob?
Guestimate - 2 kg force?
