Yes, for example, BF3. Boron will still bond with other things even though it had 6 electrons
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
In general, boron will form 3 covalent bonds, using each of its 3 valence shell electrons (sharing them). This will of course violate the octet rule, but obeys the sextet rule, and this is what makes boron stable. It (along with aluminum, eg.) do not obey the octet rule.
The octet rule is a simple rule of thumb that states that atoms tend to combine in such a way that they each have eight electrons in their valence shells, giving them the same electron configuration as a noble gas. The rule is applicable to the main group elements. In simple terms, molecules or ions tend to be most stable when the outermost electron shells of their constituent atoms contain eight electrons.
In chemistry, the octet rule states that an atom has eight electrons in its outer shell. When all eight electron orbitals are filled, the atom is described as non-reactive. Examples include neon and argon.
Protons have a positive charge and weigh 1 AMU Neutrons have a neutral charge and weigh 1 AMU Electrons have a negative charge and 1184 electrons weigh 1AMU so they are thought to add nothing to the mass of an atom. You may want to check out Bohr's model or the duet/octet rule.
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
Yes, atoms with an octet are stable and less likely to react with other elements because they have a full outer shell. Octet rule states that atoms tend to gain, lose, or share electrons to achieve a full outer shell, making them more stable.
You consider its position in the periodic table and follow the octet rule. Na is an alkaline metal, and the characteristics of these are that they will almost react with anything, especially water.
Eight
No, xenon does not always follow the octet rule. It is a noble gas and can form stable compounds that have more than eight electrons around the xenon atom, known as expanded octet.
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
when the outer most shell of an atom was said to have 8 electrons then it was said to possess an octet
The "octet rule."
There are three resonance structures for the nitrate ion that satisfy the octet rule. In each of these structures, each oxygen atom has a full octet by sharing electrons through double bonds with the nitrogen atom.
An example of a molecule that follows the octet rule is methane (CH4). In methane, carbon forms four covalent bonds with hydrogen, allowing each atom to achieve a full outer shell of electrons (octet) and satisfy the octet rule.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
A potassium atom has 1 electron in its outer shell. In order to satisfy the octet rule, it needs to donate 7 electrons to another atom to reach a stable configuration with a full outer shell.