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If a 2kg metal ball hits a 1kg wooden ball at a speed of 3ms and the metal ball continues at a speed of 1ms how fast is the wooden ball going?
This question is all about kinetic energy.
Kinetic Energy = 0.5 * mass * velocity^2
Firstly we must assume that no energy is lost to heat and sound, so that kinetic energy is constant throughout the contact.
The initial kinetic energy is all in the 2kg metal ball. Using the above formula we find that the energy is 0.5 * 2 * 3^2 = 0.5 * 2 * 9 = 9 J
The final kinetic energy must be the same (because of our assumption). The metal ball has a kinetic energy of 0.5 * 2 * 1^2 = 1 J, so the wooden ball must have the remainder, which is 8 J.
8 = 0.5 * 1 * velocity^2
velocity^2 = 16
velocity = square root of 16
velocity = 4 m/s
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