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q = mg/E

Once you get q divide it by e (1.6E-19) to get your answer. And remember, it will be negative

Explanation:

http://dev.physicslab.org/Document.aspx?doctype=3&filename=AtomicNuclear_MillikanOilDrop.xml

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Q: In Milikan's experiment an oil drop of radius 1.64 m and density 0.851 gcm3 is suspended in a chamber when a downward-pointing electric field 1.92105 NC applied Find charge on drop in terms e?
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